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4 years ago

Net force help please.

Physics

2 answers:

Nana76 [90]4 years ago

8 0

Don't get scared and make something hard out of something easy.

Just think of " N " as one strong person.

The picture shows 6 strong people pushing the box to the right, and 5 strong people pushing it back to the left. (Like some kind of tug-o-war, except they're pushing, not pulling.)

You can see that the 5 pushers on one side exactly cancel 5 of the pushers on the other side, just as if all 10 of them are not even there at all, and the only thing left is the one 'net' person on the left.

The net force on the box is 1N, pushing to the right.

nekit [7.7K]4 years ago

6 0

The net force is the total force. Add 4 and 2 together and you get 6. Since 5 N are pushing against it, you subtract that from 6. The net force is 1 N.

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Answer:

$\boxed {\boxed {\sf 412.5 \ kilometers }}$

Explanation:

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$d=s*t$

The speed of the car is 75 kilometers per hour. It traveled for 5.5 hours.

$s= 75 \ km/hr \\t= 5.5 \ hr$

Substitute the values into the formula.

$d= 75 \ km/hr * 5.5 \ hr$

Multiply. Note that the hours will cancel each other out.

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3 years ago

Draw a schematic diagram of a circuit consisting of a battery of five 2 V cells, a 5 ohm resistor, a 10 ohm resistor, a 15 ohm r

MakcuM [25]

Answer:

Current = 0.33 A

Explanation:

For diagram refer the attachment.

It is given that five cells of 2V are connected in series, so total voltage of the battery:

$\dashrightarrow \: \: \sf V = 2 \times 5 = 10 V$

Three resistor of 5 $\Omega$ , 10 $\Omega$ , 15 $\Omega$ are connected in Series, so the net resistance:

$\dashrightarrow \: \: \sf R_{n} = R_{1} + R_{2} + R_{3}$

$\dashrightarrow \: \: \sf R = 5 + 10 + 15$

${ \pink{\dashrightarrow \sf \: \: { \underbrace{R = 30 \: \Omega}}}}$

According to ohm's law:

$\dashrightarrow \sf\: \: V = IR$

$\dashrightarrow \sf \: \: I = \dfrac{V}{R}$

On substituting resultant voltage (V) as 10 V and resultant resistant, as 30 ${\pmb{\sf{\Omega}}}$ we get:

$\dashrightarrow \sf \: \: I = \dfrac{10V}{30\Omega}$

${ \pink{\dashrightarrow \sf \: \: { \underbrace{I = 0.33 A}}}}$

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