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densk [106]
3 years ago
6

Find the 90 th derivative of the function ƒ(x)=cos(x)

Mathematics
1 answer:
Inessa [10]3 years ago
5 0
F(x) = cos x
f'(x) = -sin x
f''(x) = -cos x
f'''(x) = sin x
f''''(x) = cos x

90/4 = 22 Remainder 2
Therefore, 90th derivative of f(x) = cos x is -cos x.
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Start at 3 and create a pattern with the rule add 2 what is the 5th rumber in the answer
Maru [420]

Answer:13

Step-by-step explanation:

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6 0
3 years ago
If f(x)=2x^4-3x^3+2x^2+x-3, explain how you know that the equation f(x)=0 has at least one real root between x=1 and x=2
hodyreva [135]

Answer:

Step-by-step explanation:

by theorem :

f continu in [1 , 2]

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so the equation f(x)=0 has at least one real root between x=1 and x=2

so :

7 0
3 years ago
What is the variable equal to?<br> 6x = 24<br><br> x = 5<br> x = 4<br> x = 144<br> x = 3
olganol [36]

Answer:

x=4

Step-by-step explanation:

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3 0
3 years ago
Read 2 more answers
-4(10-a)=36 what the steps
SpyIntel [72]

Hey there!☺

Answer:\boxed{a=19}

Explanation:

-4(10-a)=36 Equation

−4(10 − a) = 36  Simplify both sides

(−4)(10) + (−4)(−a) = 36 Distribute

−40 + 4a = 36

4a − 40 = 36

4a - 40 + 40 = 36 + 40 Add 40 to both sides

4a = 76

4a/4 = 76/4 Divide both sides by 4

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a = 19

Hope this helps!

8 0
3 years ago
Yoo wsg whats he units please tell meeee
dimaraw [331]

Answer:

wsp, answer is 5,5 i'm pretty sure

Step-by-step explanation:

or its 0.5

6 0
3 years ago
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