4 years ago

Find the 90 th derivative of the function ƒ(x)=cos(x)

1 answer:

5 0

F(x) = cos x
f'(x) = -sin x
f''(x) = -cos x
f'''(x) = sin x
f''''(x) = cos x

90/4 = 22 Remainder 2
Therefore, 90th derivative of f(x) = cos x is -cos x.

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What is the value of a for the exponential function in the graph represented in the form of f(x)=a(b^x)

Rina8888 [55]

Note: The complete question, along with the graph, is attached below.

Answer:

The value of a = 3

Step-by-step explanation:

Given the function

$f\left(x\right)=a\left(b^x\right)$

From the attached graph, it is clear that

at x = 0,

$f\left(0\right)=a\left(b^0\right)$

$\:f\left(0\right)\:=\:a\:\times \:1$ ∵ $b^0=1$

$f\left(0\right)=a$

Thus

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From the attached figure, it is clear that

at x = 0, the value of y = 3

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$f\left(0\right)=a$

3 = a ∵ $f\left(0\right)=y=3$

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