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densk [106]
4 years ago
6

Find the 90 th derivative of the function ƒ(x)=cos(x)

Mathematics
1 answer:
Inessa [10]4 years ago
5 0
F(x) = cos x
f'(x) = -sin x
f''(x) = -cos x
f'''(x) = sin x
f''''(x) = cos x

90/4 = 22 Remainder 2
Therefore, 90th derivative of f(x) = cos x is -cos x.
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Step-by-step explanation: Multiply 18 by -6 for B then it simplifies out.

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Can someone help me w this plz
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Lesechka [4]

Answer:

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7 0
4 years ago
Solving each system by eliminating <br> x-y+z= -1<br> x+y+3z= -3<br> 2x-y+2z= 0
Pie

There's only one system of equations here.

Let's eliminate x first,

x - y + z = -1

x = -1 + y - z

Substituting into  x + y + 3z = -3 gives

(-1 + y - z) + y + 3z = -3

2y + 2z = -2

y + z = -1

Substituting for x into 2x-y+2z = 0 gives

2(-1 + y - z) - y + 2z = 0

-2 + 2y - 2z - y + 2z = 0

y = 2

Got lucky on that one.  

z = -1 - y = -1 - 2 = -3

x = -1 + y - z = -1 + 2  - -3 = 4

Answer: x=4, y=2, z= -3

Check:

x-y+z = 4 - 2 + -3 = -1, good

x+y+3x = 4+2+3(-3) =  -3, good

2x-y+2x = 2(4)-2+2(-3) = 0, good

4 0
4 years ago
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