Answer:
Area = 160 cm²
Perimeter = 55.31 cm
Step-by-step explanation:
Applying,
Area of the figure = area of the rectangle- area of the triangle
A = lw+bh/2............... Equation 1
From the question,
Given: l = 16 cm, w = 12 cm, h = 8cm, b = 8 cm
Substitute these values into equation 1
A = (16×12)-(8×8/2)
A = 192-32
A = 160 cm²
Perimeter P = /BC/+/CD/+/DE/+/EF/+/FG/+/GA/
Applying pythagoras theorem to get /FG/
FG² = GE²+EF²
FG² = 8²+8²
FG² = 64+64
FG² = 128
FG = √128
FG = 11.31 cm
Therefore,
P = 16+12+4+8+11.31+4
P = 55.31 cm
280 your welcome good luck
A sextant<span> is a </span>doubly reflecting navigation instrument<span> that measures the </span>angular distance<span> between two visible objects. The primary use of a sextant is to measure the angle between an </span>astronomical object<span> and the </span>horizon<span> for the purposes of </span>celestial navigation<span>.
The estimation of this angle, the altitude, is known as </span>sighting<span> or </span>shooting<span> the object, or </span>taking a sight<span>. The angle and the time when it was measured, can be used to calculate a </span>position line<span> on a nautical or aeronautical </span>chart. F<span>or example; sighting the </span>Sun<span> at </span>noon <span>or </span>Polaris<span> at night (in the Northern Hemisphere) to estimate </span>latitude<span>. Sighting the height of a landmark can give a measure of </span>distance off<span> and held horizontally.
A sextant can measure angles between objects for a </span>position on a chart.<span> A sextant can also be used to measure the </span>lunar distance<span> between the moon and another celestial object (such as a star or planet) in order to determine </span>Greenwich Mean Time<span> and hence </span>longitude<span>.
Hope this helps!
<em>~ ShadowXReaper069</em></span>
Hai!!! Your answer is both x=-10 and x=10
