Answer:
A. P(R ∩ W)= 0.24
B. P(W)= 0.38
Step-by-step explanation:
Hello!
Purchased (W) Did not purchase (NW)
<u> extendend warranty extendend warranty </u>
Regular 0.24 0.56
<u>Price (R) </u>
Sale 0.14 0.0599999999999999
<u>Price (S) ≅ 0.06 </u>
<u />
The owner whats to know if there is a relationship between the price of a sod item ( regular; sale) and the decision of buying an extended warranty. The contingency table above shows the results of the probabilities she produced after analyzing her records.
A. What id the probability that a customer who bought an item at the regular price (R) purchased the extended warranty (W)?
The asked probability is an intersection between "regular price" and "purchased the warranty", symbolically:
P(R ∩ W)= 0.24
The probability is in the table.
B. What is the probability that a customer buys an extended warranty?
To calculate the probability you have to take into account all possible outcomes that include purchasing an extended warranty, in this case, is "regular price + extended warranty" and "sales price + warranty" it is the total of the firs column:
P(W) = 0.24 + 0.14= 0.38
I hope it helps!