3 years ago

How do I simplify the expression

Mathematics

1 answer:

Serggg [28]3 years ago

3 0

Answer:

Like this. -2x+10

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Which is the correct way to represent 0.0035 kg by using scientific notation? –3.5 103 kg –3.5 10–3 kg 3.5 10–3 kg 3.5 103 kg?

Vlada [557]

It would be

3.5 × 10⁻³ kg.

The decimal point must be moved 3 places to the right in order to have it behind the first non-zero digit; this gives us the exponent of 3, and since we are moving the decimal to the right, it is a negative exponent.

5 0

3 years ago

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Find the vectors T, N, and B at the given point. r(t) = < t^2, 2/3t^3, t >, (1, 2/3 ,1)

maxonik [38]

Answer with Step-by-step explanation:

We are given that

$r(t)=< t^2,\frac{2}{3}t^3,t >$

We have to find T,N and B at the given point t > (1, $2/3$ ,1)

$r'(t)=$

$\mid r'(t) \mid=\sqrt{(2t)^2+(2t^2)^2+1}=\sqrt{(2t^2+1)^2}=2t^2+1$

$T(t)=\frac{r'(t)}{\mid r'(t)\mid}=\frac{}{2t^2+1}$

Now, substitute t=1

$T(1)=\frac{}{2+1}=\frac{1}{3}$

$T'(t)=\frac{-4t}{(2t^2+1)^2} +\frac{1}{2t^2+1}$

$T'(1)=-\frac{4}{9}+\frac{1}{3}$

$T'(1)=\frac{1}{9}=$

$\mid T'(1)\mid=\sqrt{(\frac{-2}{9})^2+(\frac{4}{9})^2+(\frac{-4}{9})^2}=\sqrt{\frac{36}{81}}=\frac{2}{3}$

$N(1)=\frac{T'(1)}{\mid T'(1)\mid}$

$N(1)=\frac{}{\frac{2}{3}}=$

$N(1)=$

$B(1)=T(1)\times N(1)$

$B(1)=\begin{vmatrix}i&j&k\\\frac{2}{3}&\frac{2}{3}&\frac{1}{3}\\\frac{-1}{3}&\frac{2}{3}&\frac{-2}{3}\end{vmatrix}$

$B(1)=i(\frac{-4}{9}-\frac{2}{9})-j(\frac{-4}{9}+\frac{1}{3})+k(\frac{4}{9}+\frac{2}{9})$

$B(1)=-\frac{2}{3}i+\frac{1}{3}j+\frac{2}{3}k$

$B(1)=\frac{1}{3}$

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3 years ago

10. Find the rate of change in the table below.

Natasha_Volkova [10]

Answer:

it's times 4 every time

Step-by-step explanation:

4.5 times 4 is 18 etc

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3 years ago

4x + 1 = 5, find x assuming x is a whole number

levacccp [35]

Answer:

x=1

Step-by-step explanation:

4x+1=5

4x=5-1

4x=4

x=4/4=1

This happens to be a whole number.

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3 years ago

Approximate 0.3632 to 2 decimal places

tamaranim1 [39]

Answer:

0.36

I hope this helps

8 0

3 years ago

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