Given:
A diagram of a composite figure.
Radius of cone and hemisphere is 8 cm.
Height of the cone is 15 cm.
To find:
The volume and the surface area of the composite figure.
Solution:
Volume of a cone is:

Where, r is the radius and h is the height of the cone.
Putting
in the above formula, we get



Volume of the hemisphere is:

Where, r is the radius.
Putting
, we get



Now, the volume of the composite figure is:



The volume of the composite figure is 661.3π cm³.
The curved surface area of a cone is:

Where, r is the radius and h is the height of the cone.
Putting
in the above formula, we get




The curved surface area of the hemisphere is:

Where, r is the radius.
Putting
, we get



Total surface area of the composite figure is:



The total surface area of the composite figure is 264π cm².
Therefore, the correct option is A.