421/10= 42.1 vans since you can’t bring a 0.1 van you’ll have to bring a whole extra van so 43 vans
answer: one person will be in the partially full van
Answer:
4,6,8
Step-by-step explanation:
Let x = 1st even integer
x+2 =2nd even integer
x+4 =3nd even integer
x+ x+2 + x+4 = 18
Combine like terms
3x+6 = 18
Subtract 6 from each side
3x+6-6=18-6
3x= 12
Divide by 3
3x/3 =12/3
x = 4
x+2 = 6
x+4 = 8
The triangle to solve for has a leg or 12 feet, hypotenuse of 20 feet, so solve for Pythagoras

for a

a = 16 feet
Answer:
(x + 1)² = 7
Step-by-step explanation:
Given:
-2x = x² - 6
We'll start by rearranging it to solve for zero:
x² + 2x - 6 = 0
The first term is already a perfect square so that's fine. Normally, if that term had a non-square coefficient, you would need to multiply all terms a value that would change that constant to a perfect square.
Because it's already square (1), we can simply move to the next step, separating the -6 into a value that can be doubled to give us the 2, the coefficient of the second term. That value will of course be 1, giving us:
x² + 2x + 1 - 1 - 6 = 0
Now can group our perfect square on the left and our constants on the right:
x² + 2x + 1 - 7= 0
x² + 2x + 1 = 7
(x + 1)² = 7
To check our answer, we can solve for x:
x + 1 = ± √7
x = -1 ± √7
x ≈ 1.65, -3.65
Let's try one of those in the original equation:
-2x = x² - 6
-2(1.65) = 1.65² - 6
- 3.3 = 2.72 - 6
-3.3 = -3.28
Good. Given our rounding that difference of 2/100 is acceptable, so the answer is correct.
Answer: x=4.41 y= -7.35
Step-by-step explanation:
Pretty basic just graph them using Desmos...
Showing your work you would need to get x on one side then y on the other.
Because 3y is positive I personally like to use that one first. The inverse operation of 3y is divide so you divide 3y by 3 and the 3s cancel out. Divide -22.05 by 3 and you get -7.35. Which is your y value.
Finding X is a bit more difficult, you need to divide by -5 which is the obvious inverse operation. So, -22.05/-5 and you get 4.41. Which is your X value.
Any further questions feel free to contact me.
-Vy