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musickatia [10]

3 years ago

14

6/9 x 6 x 5.2 NEED HELP IMMEDIATELY

1 answer:

chubhunter [2.5K]3 years ago

8 0

Answer:

The answer is 20.8

Step-by-step explanation:

I hope this is right. Sorry if i'm wrong

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Using the linear combination method what is the solution to the system of linear equations 7x - 2y = -20 and 9x + 4y = -6

Ghella [55]

x should equal -2 and y should equal -3 to solve this i multiplied the first equation by 2 then got rid of the 4y and -4y then i added the 14x to the 9 equaling 23x and added the -40 to the -6 which became 23x=-46 i solved this getting -s for x, then i plugged that into the equations to get y which was -3

8 0

4 years ago

Which relation represents a function?

trasher [3.6K]

Answer:

(-2, 2), (0, 2), (7, 2), (11, 2)

Step-by-step explanation:

A relation must have no repeating x-values for it to be a function.

Set C does not have any repeating x-values, so it is a function.

Sets A, B, and D have repeating x-values, so they are not functions.

A: (0, 0), (2, 3), (2, 5), (6, 6)

B: (3, 5), (8, 4), (10, 11), (10, 6)

D: (13, 2), (13, 3), (13, 4), (13, 5)

4 0

3 years ago

Read 2 more answers

Pleaseeeeeeeeeeeee help me!!!!!

Aneli [31]

Answer is 150/x see photo for solution

4 0

4 years ago

Drag tiles to fill in the blanks to complete the expression that could be used to predict the number of winners of a game. Tiles

ziro4ka [17]

Answer:

First blank - A)Total Number of Possible Outcomes

Second blank - B)Number of Winners

Step-by-step explanation:

The exact question is as follows :

We know that,

Probability of an event is equals to Total number of Favorable outcomes divided by Total number of outcomes

So,

P(event) = Number of favorable outcomes ÷ Total Number of Possible Outcomes

As we have to predict the Number of winners of a game

So,

P(Number of winner) = Number of winners ÷ Total number of Contestants

∴ we get

P(event) = Number of favorable outcomes ÷ Total Number of Possible Outcomes

= Number of winners ÷ Total number of Contestants

4 0

3 years ago

Prove that is here<br><img src="https://tex.z-dn.net/?f=1%20-%20cos%20%7B2%7Da%20%5Cdiv%201%20-%20sin%20a%7B2%7D%20%20%3D%20tan%

garri49 [273]

$\\ \sf\longmapsto \dfrac{1-cos2A}{1-sin2A}$

<h3>LHS</h3>

$\boxed{\sf \dfrac{cosA}{sinA}=cotA}$

$\\ \sf\longmapsto \dfrac{1-cos2A}{1-sin2A}$

$\\ \sf\longmapsto 1-cot2A$

$\\ \sf\longmapsto 1-\dfrac{1}{tan2A}$

$\\ \sf\longmapsto \dfrac{tan2A-1}{tan2A}$

$\\ \sf\longmapsto tan2A$

8 0

3 years ago