Something is wrong here, the slope is off...
m=(y2-y1)/(x2-x1)
m=(1-3)/(12--4)
m=-2/16
m=-1/8
So the point slope form should be:
y-1=(-1/8)(x-12)
The standard form of the line is ax+by=c so we need to rearrange it to reflect the this form...multiply both sides by -8 to get:
8-8y=x-12 subtract 8 from both sides
-8y=x-20 subtract x from both sides
-x-8y=-20 by convention, the coefficient of x should be positive, multiply both sides by -1
x+8y=20
....
Just to show that the equation given you is incorrect..
y-1=(x-12)/4 using the point (-4,3)
3-1=(-4-12)/4
2=-16/4
2=-4 which is obviously incorrect...(they had the wrong slope for the two points given)
Here the graph y=x²
Taking the 1st derivative here of the y it will be
y1 = 2x
m=-1/3
That is m=2x
so x=-1/6
so y=(-1/6)²=1/36
So the coordinate of point will be=(-1/6 , 1/36)
I don’t think I just want points
<u>(83.9 × 10^12)(2.87 × 10^-³)</u>
3.76 × 10²
<u>(83,900,000,000,000)(0.00287)</u>
376
<u>240,793,000,000</u>
376
640,406,914.9
