The solution to the system is (-2,-8)
The answer is y=1/4x because the y-intercept is zero and the slope is 1/4.
Answer:
Sqrt (11/8)
Step-by-step explanation:
Sec^2 - Tan^2 = 1
- Tan^2 = 1 - Sec^2
Tan^2 = -1 + Sec^2
Tan^2 = 3/8
3/8 = -1 + Sec^2 Theta
1 + 3/8 = Sec ^2 Theta
11/8 = Sec^2 Theta
Sqrt ( 11/8) = Sec of theta
-- Gage Millar, Algebra 1/2 Tutor (Pending Pre-Calc Tutor)
Answer:
1) x ≤ 2 or x ≥ 5
2) -6 < x < 2
Step-by-step explanation:
1) We have x^2 - 7x + 10, so let's factor this as if this were a regular equation:
x^2 - 7x + 10 = (x - 2)(x - 5)
So, we now have (x - 2)(x - 5) ≥ 0
Let's imagine this as a graph (see attachment). Notice that the only place that is above the number line is considered greater than 0, and that's when x ≤ 2 or x ≥ 5 (the shaded region).
2) Again, we have x^2 + 4x - 12, so factor this as if this were a regular equation:
x^2 + 4x - 12 = (x + 6)(x - 2)
So now we have (x + 6)(x - 2) < 0
Now imagine this as a graph again (see second attachment). Notice that the only place that is below 0 (< 0) is when -6 < x < 2 (the shaded region).
Hope this helps!
Answer:
A
Step-by-step explanation:
(x+2)(x^2 - 1)
Foil!
(x * x^2) + (x * -1) + (2 * x^2) + (2 * -1) =
x^3 +2x^2 - x - 2