3 years ago

How many cubic blocks of side length

Mathematics

1 answer:

Tom [10]3 years ago

7 0

Answer:

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A bag contains 42 red marbles, 6 white marbles, and 8 gray marbles. You randomly pick out a marble, record its color, and put it

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For any single draw,

$\mathbb P(\text{white})=\dfrac6{42+6+8}=\dfrac6{56}$
$\mathbb P(\text{gray})=\dfrac8{42+6+8}=\dfrac8{56}$

Drawing a white marble or a gray marble are disjoint events; only one of them can happen. So

$\mathbb P(\text{white or gray})=\mathbb P(\text{white})+\mathbb P(\text{gray})-\underbrace{\mathbb P(\text{white and gray})}_0$
$\mathbb P(\text{white or gray})=\dfrac6{56}+\dfrac8{56}=\dfrac{14}{56}$

Out of 224 draws, you should expect $\dfrac{14}{56}\times224=56$ of the marbles to be either white or gray.