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Vikentia [17]
2 years ago
6

For the transformation shown, triangle ABC

Mathematics
1 answer:
borishaifa [10]2 years ago
8 0

For the transformation shown, triangle ABC is called the pre-image

<h3>How to determine triangle ABC</h3>

From the figure, we have the following highlights

  • There are two triangles in the figure (ABC and A'B'C')
  • Triangle ABC is transformed to triangle A'B'C'

Given that a triangle is transformed to another,

It means that, the first triangle is the pre-image, while the second is the image

Hence,  triangle ABC is called the pre-image.

Read more about transformation at:

brainly.com/question/1548871

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Help someone please ASAP
Klio2033 [76]

1.

3 x 4 = 12

3 + 4 = 12

The two integers a and b are : 3 and 4


2.

-4 x 1 = -4

-4 + 1 = -3

The two integers a and b are : -4 and 1


3.

-3 x -3 = 9

-3 + -3 = -6

The two integers a and b are : -3 and -3


There you go! I really hope this helped, if there's anything just let me know! :)

7 0
3 years ago
The table shows a direct variation.
lakkis [162]
2.4 because 4.8/2 is 2.4. 14.4/4 is also 2.4. Constant of variation is the unit rate
4 0
3 years ago
Paul and jose are trying to measure the height of a tree. paul is standing 19m from the foot of the tree and measures the angle
Nina [5.8K]
The firts thig we are going to do is create tow triangles using the angles of elevation of Paul and Jose. Since the problem is not giving us their height we'll assume that the horizontal line of sight of both of them coincide with the base of the tree.
We know that Paul is 19m from the base of the tree and its elevation angle to the top of the tree is 59°. We also know that the elevation angle of Jose and the top of the tree is 43°, but we don't know the distance between Paul of Jose, so lets label that distance as x.
Now we can build a right triangle between Paul and the tree and another one between Jose and the tree as shown in the figure. Lets use cosine to find h in Paul's trianlge:
cos(59)= \frac{19}{h}
h= \frac{19}{cos(59)}
h=36.9
Now we can use the law of sines to find the distance x between Paul and Jose:
\frac{sin(43)}{36.9} = \frac{sin(16)}{x}
x= \frac{36.9sin(16)}{sin(43)}
x=14.9

Now that we know the distance between Paul and Jose, the only thing left is add that distance to the distance from Paul and the base of the tree:
19m+14.9=33.9m

We can conclude that Jose is 33.9m from the base of the tree.

3 0
3 years ago
1000p for an answer pleaseeeeee
zepelin [54]
X=17.3
but the 3 has a line above. which means repeated 
4 0
3 years ago
Read 2 more answers
A square rotated about its center by 360º maps onto itself at different angles of rotation. You can reflect a square onto itself
harkovskaia [24]

A square rotated about its center by 360º maps onto itself at 4 different angles of rotation. You can reflect a square onto itself across 4 different lines of reflection.

8 0
3 years ago
Read 2 more answers
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