All categories

1 year ago

For the transformation shown, triangle ABC

Mathematics

1 answer:

borishaifa [10]1 year ago

8 0

For the transformation shown, triangle ABC is called the pre-image

<h3>How to determine triangle ABC</h3>

From the figure, we have the following highlights

There are two triangles in the figure (ABC and A'B'C')
Triangle ABC is transformed to triangle A'B'C'

Given that a triangle is transformed to another,

It means that, the first triangle is the pre-image, while the second is the image

Hence, triangle ABC is called the pre-image.

You might be interested in

What is the value of x?<br> Enter your answer in the box.

loris [4]

Answer:

Step-by-step explanation:

Since all the angles are the same in this triangle, all the sides should be the same too.

Hence, 3x - 5 = 4x - 30

5 + -1x = -30

-1x = -35

x = 35

Hope this helped!

8 0

2 years ago

Read 2 more answers

A 10-foot ladder is leaning against a vertical wall. If the bottom of the ladder is being pulled away from the wall at the rate

Alex777 [14]

Answer:

The area is changing at 15.75 square feet per second.

Step-by-step explanation:

The triangle between the wall, the ground, and the ladder has the following dimensions:

H: is the length of the ladder (hypotenuse) = 10 ft

B: is the distance between the wall and the ladder (base) = 6 ft

L: the length of the wall (height of the triangle) =?

dB/dt = is the variation of the base of the triangle = 9 ft/s

First, we need to find the other side of the triangle:

$H^{2} = B^{2} + L^{2}$

$L = \sqrt{H^{2} - B^{2}} = \sqrt{(10)^{2} - B^{2}} = \sqrt{100 - B^{2}}$

Now, the area (A) of the triangle is:

$A = \frac{BL}{2}$

Hence, the rate of change of the area is given by:

$\frac{dA}{dt} = \frac{1}{2}[L*\frac{dB}{dt} + B\frac{dL}{dt}]$

$\frac{dA}{dt} = \frac{1}{2}[\sqrt{100 - B^{2}}*\frac{dB}{dt} + B\frac{d(\sqrt{100 - B^{2}})}{dt}]$

$\frac{dA}{dt} = \frac{1}{2}[\sqrt{100 - B^{2}}*\frac{dB}{dt} - \frac{B^{2}}{(\sqrt{100 - B^{2}})}*\frac{dB}{dt}]$

$\frac{dA}{dt} = \frac{1}{2}[\sqrt{100 - 6^{2}}*9 - \frac{6^{2}}{\sqrt{100 - 6^{2}}}*9]$

$\frac{dA}{dt} = 15.75 ft^{2}/s$

Therefore, the area is changing at 15.75 square feet per second.

I hope it helps you!

5 0

2 years ago

Can the probability of an event ever be greater than 1? Explain your answer

givi [52]

Answer:

No you can not

Step-by-step explanation:

You cant have a probability greater than 1 because then the probability would be false

7 0

2 years ago

Read 2 more answers

A rectangular prism with a length of 5 centimeters, height of 3 centimeters, and width of 4 centimeters. The rectangular prism s

sveta [45]

Answer:

94cm squared

Step-by-step explanation:

you find the area of each side by doing base times height and you add the six of them all together to get your answer

3 0

2 years ago

Read 2 more answers

What s this pls helpppppp

Nutka1998 [239]

Answer:

Step-by-step explanation:

6 0

2 years ago

Read 2 more answers