15 POINTS... NEED HELP! Write an equation in point-slope form of a line which is perpendicular to x + 5y = 5 and passes through
1 answer:
Answer:
y + 1 = 5(x - 10)
Step-by-step explanation:
the equation of a line in point- slope form is
y - b = m(x - a)
where m is the slope and (a, b) a point on the line
the equation of a line in slope- intercept form is
y = mx + c ( m is the slope and c the t-intercept )
rearrange x + 5y = 5 into this form ( subtract x from both sides )
5y = - x + 5 ( divide all terms by 5 )
y = - x + 1 ← in slope- intercept form
with slope m = -
given a line with slope m then the slope of a line perpendicular to it is
= -
= -
= 5
using m = 5 and (a, b) = (10, - 1), then
y + 1 = 5(x - 10) ← in point- slope form
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Answer:
<h2>y = 1</h2>Step-by-step explanation:
The point-slope form of an equation of a line:
<em>m</em><em> - slope</em>
<em>(x₁, y₁)</em><em> - point on a line</em>
We have <em>m = 0, (3, 1) → x₁ = 3, y₁ = 1</em>.
Substitute:
<em>add 1 to both sides</em>
Other method.
If the slope is equal 0, then it's a horizontal line.
The equation of a horizontal line: <em>y = a</em>.
We have the point on a line (3, 1) → x = 3, y = 1.
Therefore the equation is <em>y = 1</em>.