Question

15 POINTS... NEED HELP! Write an equation in point-slope form of a line which is perpendicular to x + 5y = 5 and passes through the point (10, -1).

Answer 1

Answer:

y + 1 = 5(x - 10)

Step-by-step explanation:

the equation of a line in point- slope form is

y - b = m(x - a)

where m is the slope and (a, b) a point on the line

the equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the t-intercept )

rearrange x + 5y = 5 into this form ( subtract x from both sides )

5y = - x + 5 ( divide all terms by 5 )

y = - $\frac{1}{5}$ x + 1 ← in slope- intercept form

with slope m = - $\frac{1}{5}$

given a line with slope m then the slope of a line perpendicular to it is

$m_{perpendicular}$ = - $\frac{1}{m}$ = - $\frac{1}{-1/5}$ = 5

using m = 5 and (a, b) = (10, - 1), then

y + 1 = 5(x - 10) ← in point- slope form