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3 years ago

How do you find the average rate of change in calculus?

1 answer:

8 0

The average rate of change doesn't require calculus.
It's just

(amount of change during some time) / (amount of time for the change) .

You need calculus when you want the instantaneous rate of change . . .
that's the rate of change at a single point in time.

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PLZ ASWER ASAP!!!!!!!!!!!

geniusboy [140]

Answer:

f(x) = 6x² - 24x + 21

Step-by-step explanation:

The equation of a quadratic function in vertex form is

f(x) = a(x - h)² + k

where (h, k) are the coordinates of the vertex and a is a multiplier

Here (h, k ) = (2, - 3 ) , then

f(x) = a(x - 2)² - 3

To find a substitute (1, 3 ) into the equation

3 = 1(1 - 2)² - 3

3 = a(- 1)² - 3

3 = a - 3 ( add 3 to both sides )

6 = a

f(x) = 6(x - 2)² - 3 ← in vertex form

= 6(x² - 4x + 4) - 3

= 6x² - 24x + 24 - 3

f(x) = 6x² - 24x + 21 ← in standard form

4 0

3 years ago

(1) a) 5270 cl= ? dal

Ivanshal [37]

Answer:

Check below

Step-by-step explanation:

1) These metric volume units can be easily converted by dividing or multiplying by 10 and its multiple. Like this: each step up on the ladder multiply by 10. Each step down divide by 10

$a)5270 \:cl=527\:dl\\b)kl=5.3 \times 10=530 hl\\c)58000ml=5.8 dal =(\frac{58000}{10000})\\d)0.39 dal=3.9 l\\e)7.8 dal=780 dl\\f)57.2 ml=5.72 cl$ .

2) When it comes to area, the "ladder scheme" remains valid but now we'll multiply or divide by

$10^3$

Bear in mind these useful relations:

$1litre =\frac{1}{10^3}m^{3}$

$1 cm^{3} =1 ml$

$a) 3.7 l=3700 cm^{3}\\b)29.6 dm^{3}\\29.6 dm^{3} \rightarrow 29.6\times10^{3} cm^3=29.6\times10^{3} ml = 29.6\times10^{2} cl \:or\:2960 cl\\c)8.1l=8100 cm^{3}\\d)5l=\frac{5}{10^{-3}} m^{3}\\e)5.2 cl=52ml=52 cm^{3}=52\times10^{3}=52000 \:mm^{3}\\f)375 ml=375 cm^{3}\\g) 1300 cm^{3}=1300 ml=13 dl\\h) 8.6 ml= 8.6 cm^{3}\times\: 10^{3}=8600 mm^{3}\\i) 51.8\times 10^{11} l \rightarrow 51.8\times 10^{-11}km^{3}$

6 0

3 years ago

How many feet are shorter than 20 centimeters

Veseljchak [2.6K]

1 foot is shorter that 20 centimeters

8 0

4 years ago

Given $dc = 7$, $cb = 8$, $ab = \frac{1}{4}ad$, and $ed = \frac{4}{5}ad$, find $fc$. Express your answer as a decimal.

Pachacha [2.7K]

A ↔ B ↔ C ↔ D ↔ E ↔ F

$\frac{1}{4} AD$ 8 7 $\frac{4}{5} AD$ ???

AB + BC + CD = AD segment addition postulate

$\frac{1}{4} AD$ + 8 + 7 = AD

$\frac{1}{4} AD$ + 15 = AD

AD + 60 = 4AD

60 = 3AD

20 = AD

AB = $\frac{1}{4} AD$ = $\frac{1}{4}(20)$ = 5

DE = $\frac{4}{5}AD$ = $\frac{4}{5}(5)$ = 4

CD + DE + EF = CF segment addition postulate

7 + 4 + EF = CF

11 + EF = CF

Answer: 11 + EF

Note: You did not provide any info about EF. If you have additional information that you did not type in, calculate EF and add it to 11 to find the length of CF.

7 0

3 years ago

Read 2 more answers

Help now please help me with this assignment

slega [8]

Answer:

Since 3⁵= 243 you can just multiply by 3 to find 3⁶

6 0

2 years ago

Read 2 more answers