point B is located in quadrant II (option B)
Explanation:
Point A: (6, 3) = (x, y)
reflection of point A across the y axis:
The x coordinate will be negative and the y coordinate will remain the same
reflection of point A across the y axis = (-6, 3)
Attaching the graph showing the point after reflection:
Since point B is the reflection of point A.
Hence, point B is located in quadrant II (option B)
I got this answer from someone else so I’m not sure this is correct but I really hope it helps...
Step-by-step explanation:
Look for patterns in the derivatives.
y=cos2x
y'=-2sin2x
y''=-4cos2x
y'''=8sin2x
y''''=16cos2x
Notice that sin and cos alternate every derivative. Also, they alternate positive and negative every 2 derivatives.
The constant is just 2^(derivative#).
Every odd derivative has sin and every even derivative has cos, so you know that the 30th derivative will be cos.
If you follow the pattern of negatives and positives, you find that the 30th derivative will be negative.
y^(30)= -2^30cos2x
y^(30)= -1073741824cos2x
Answer:
Option A.) is correct 
by AA similarity. There are two angles that are congruent given by 
.
This is because both pairs represent alternate interior angles formed by lines intersecting two parallel lines.
Step-by-step explanation:
From the given figure we can say that
i) Option A.) is correct by AA similarity. There are two angles that are congruent given by .
This is because both pairs represent alternate interior angles formed by lines intersecting two parallel lines.
71 is the answer. If you round it, it would be 70.
Answer:
x=3
Step-by-step explanation:
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