Question

Which equation represents a line that passes through (4, left-parenthesis 4, StartFraction one-third EndFraction right-parenthesis.) and has a slope of StartFraction 3 Over 4 EndFraction.?
y – y minus StartFraction one-third EndFraction equals StartFraction 3 Over 4 EndFraction left-parenthesis x minus 4 right-parenthesis. = y minus StartFraction 3 Over 4 EndFraction equals StartFraction one-third EndFraction left-parenthesis x minus 4 right-parenthesis.(x – 4)

y – y minus StartFraction one-third EndFraction equals 4 left-parenthesis x minus StartFraction 3 Over 4 EndFraction right-parenthesis. = y minus StartFraction one-third EndFraction equals StartFraction 3 Over 4 EndFraction left-parenthesis x minus 4 right-parenthesis.(x – 4)

y – y minus StartFraction one-third EndFraction equals 4 left-parenthesis x minus StartFraction 3 Over 4 EndFraction right-parenthesis. = 4(x – )

y – 4 = y minus 4 equals StartFraction 3 Over 4 EndFraction left-parenthesis x minus StartFraction one-third EndFraction right-parenthesis.(x – )

Answer 1

Answer:

$y-\frac{1}{3}=\frac{3}{4}(x-4)$

Step-by-step explanation:

we know that

The equation of the line into point slope form is equal to

$y-y1=m(x-x1)$

In this problem we have

$point\ (4,\frac{1}{3})$

$m=\frac{3}{4}$

substitute the given values

$y-\frac{1}{3}=\frac{3}{4}(x-4)$

y minus StartFraction one-third EndFraction equals StartFraction 3 Over 4 EndFraction left-parenthesis x minus 4 right-parenthesis.(x – 4)

Answer 2

Answer:

B

Step-by-step explanation: