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sammy [17]
3 years ago
13

A polynomial function has a zeros at -1,2,7 and all are multiplicity of 1 write a function in standard form that could represent

this function
Mathematics
1 answer:
Colt1911 [192]3 years ago
8 0

Answer:

x^3 + 6x^2 - 9x - 14

Step-by-step explanation:

The zeros of a polynomial are the solutions to its factors. When the factors are set equal to 0, the zeros are the result. To write the equation, use the zeros to reverse the process to find the factors which multiply to make the equation.

x = -1 results from the factor x + 1 = 0

x = 2 results from the factor x - 2 = 0

x = 7 results from the factor x - 7 = 0

Since all zeros have multiplicity of 1, this means there is no exponent on the factored expressions. So the equation of the polynomial is (x+1)(x-2)(x-7).

Multiply the factors using the distributive property to find the equation in standard form.

(x+1)(x-2)(x-7)

(x^2 + 1x -2x - 2)(x+7)

(x^2 - x - 2)(x+7)

x^3 - x^2 - 2x + 7x^2 - 7x - 14

x^3 + 6x^2 - 9x - 14

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\red { \green {\boxed {\boxed{Answer}}}}

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And we can solve for B_x and we got:

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Step-by-step explanation:

For this case we know that the midpoint for the segment AB is (2,5)

And we know that the coordinates of A are (1,2)

We know that for a given segment the formulas in order to find the midpoint are given by:

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