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4 years ago

7

ANswer this question!!!!!

1 answer:

4vir4ik [10]4 years ago

6 0

<u><em>Its Going to Be Table B! Good Luck :)⇔</em></u>

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What is the total amount you would have to pay back on a $4500 loan at 5% for 3 years?

noname [10]

Answer:

675

Step-by-step explanation:

5% of 4500 is 225

225 x 3 = 675

675 + 4500 = 5175

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3 years ago

The ratio of peanut butter to cookie dough is 1:5. Which of the following best describes the amount of peanut butter and cookie

aleksley [76]

I believe the answer is the 3rd choice

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3 years ago

What is the result of adding these two equations?<br> 5x - 9y = 1<br> - 7x + 2y = -5

Vlada [557]

Answer: −2x−7y=−4

Step-by-step explanation:

that is the full correct answer

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3 years ago

43. Find the equation of a line perpendicular to the y-axis passing through the point (4, 7).

iVinArrow [24]

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Answer:

y = 7

Step-by-step explanation:

The y-axis is the vertical line x=0. A perpendicular line will be a horizontal line that will have an equation of the form ...

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6 0

3 years ago

The gate of a stadium ha two pillars each of height 10ft.with four visible lateral faces and 3ft*3ft bases .the top of eaxh pill

lbvjy [14]

The pillars and the pyramids in the stadium gate means that we have to calculate the area of the items that make up the gate one after the other. At the end of the calculation, the calculated areas are then added up.

The total cost of painting is Rs.21344

First, we calculate the area of 1 side of 1 pillar using:

$A = Height * Base$

Where

$Height = 10ft$ --- Height of the pillar

$Base = 3ft$ --- Base of the pillar

So:

$A = 10ft * 3ft$

$A = 30ft^2$

The area of the 4 sides of the pillar is:

$A_2 = 4 * A$ --- i.e. 4 multiplied by the area of 1 side

$A_2 = 4 * 30ft^2$

$A_2 = 120ft^2$

The area of the 2 pillars is:

$Area_1 = 2 * A_2$ --- i.e. 2 multiplied by the area if 1

$Area_1 = 2 * 120ft^2$

$Area_1 = 240ft^2$

Because one part of the pyramid won't be visible, we calculate the area of the pyramid using:

$Area = lw + l\sqrt{(w/2)^2 + h^2} + w\sqrt{(l/2)^2 + h^2}$

Where:

$h = 2$ -- the height

$l = w = 3$ --- the base of the pillar is the length and width of the pyramid.

So, we have:

$Area = 3\sqrt{(2/2)^2 + 2^2} + 3\sqrt{(2/2)^2 + 2^2}$

$Area = 3\sqrt{1 + 4} + 3\sqrt{1 + 4}$

$Area = 3\sqrt{5} + 3\sqrt{5}$

$Area = 6\sqrt{5}$

For the two pyramids, the area is:

$Area_2 = 2 * 6\sqrt 5$ -- 2 multiplied by area of 1

$Area_2 = 12\sqrt 5$

$Area_2 = 26.8$

So, the total area to be painted is:

$Total = Area_1 + Area_2$ --- the sum of the area of the pillars and the pyramids

$Total = 240+26.8$

$Total = 266.8ft^2$

The unit cost of paint is:

Rate = Rs80 per sq.ft

The total cost of painting is:

$Cost = 80 * 266.8$

$Cost = Rs.21344$

Read more at:

brainly.com/question/14320476

7 0

3 years ago