Answer:
maximum 4 Mimimum I'm 0 or maximum 10 minimum 0
Answer:
78
Step-by-step explanation:
The IQR is quartile 3 - quartile 1. First, we need to find the mean of the dataset, which is 50 -- the fifth number. Then, the median of the dataset on the left of the fifth number is the first quartile, and the median of the dataset on the right is the third. We get Q1 to then be halfway between 30 and 50, or 40, and Q3 to be halfway between 56 and n, so Q3 = (56+n)/2. Since we need Q3-Q1=27, or (56+n)/2-40=27, we have (56+n)/2=67 and 56+n=134, so n = 134-56=78
Answer: Marked Prixe = Rs. 1800
Step-by-step explanation:
Let the marked price be M
1) A retailer allowed 12% discount and sold a T-shirt at a loss of Rs 16.
SP = 0.88M
CP - SP = 16
CP = 16 + SP
CP = 16 + 0.88M
2) If he had sold it at 10% discount he would have gained Rs 20.
SP = 0.9M
SP - CP = 20
0.9M = 20 + CP
CP = 0.9M - 20
16 + 0.88M = 0.9M - 20
0.9M - 0.88M = 20+16
0.02M = 36
36 = 0.02M
M = 1800
I’m not sure but good luck with your test
Use BODMAS or BIDMAS (Brackets, over Indices, Division, Multiplication, Addition, the Subtraction, this tells you which order to do things in)
As you cant do √10 in the brackets you do the indices, so (√10)³
Split this up to make it easier
(√10)³= √10 x √10 x √10 = 10√10
You the multiply this by 9
9 x 10√10 = 90√10
then multiply by 5
5 x 90√10 = 450√10 = 1423.024947 (using calculator)
