7w+5=3w-15 what is the answer

A rectangular garden is extended 4% on the long sides and 8% on the short sides. To the nearest hundredth of a percent, by what

liq [111]

Answer: 12.32%

Step-by-step explanation:

1. $x$ is the original long side and $y$ is the original short side.

2. The area of the original rectangle is $xy$ .

3. The rectangle is extended 4% on the long sides and 8% on the short sides. therefore, the new long side is:

$\frac{104}{100}x=\frac{26}{25}x$

4. And the new short side is:

$\frac{108}{100}y=\frac{27}{25}y$

5. The new area is:

$(\frac{26}{25}x)(\frac{27}{25}y)=\frac{702}{625}xy$

6. The percentage of increase is calculated by substracting the new area and the original area:

$\frac{702}{625}xy-xy=0.1232xy$

7. The result is:

(0.1232)(100)=12.32%

3 0

3 years ago

HELP ASAP !!! Which of the following are identities? Check all that apply.

anastassius [24]

Answer:

A,CAND D

Step-by-step explanation:

ADD ME AS BRAINLIEST

6 0

2 years ago

Read 2 more answers

There are 7 coins that look identical.One of the seven coins weighs slightly less than the other 6. Using a balance scale, how c

RoseWind [281]

Start by putting two coins on each side of the scale. If one side is higher, then the light coin must be in that pair (use a second weighing to determine which of that pair is the lightest.)
If the initial weighing shows the two pairs to be even, discard those four and go to the three others. Put two of the coins on the scale - one on each side. If one side stays higher, that coin is your light one. If however they are equal, the final unweighed coin must be the lighter coin.

5 0

3 years ago

You are randomly selecting 3 cans of regular and diet cola, but assume that there are 6 cans of regular cola and 7 cans of diet

gayaneshka [121]

Answer:0.367

Step-by-step explanation:

Given

There are 6 cans of regular and 7 cans of diet cola

number of ways of selecting 2 regular colas and 1 can of diet cola is

$\Rightarrow ^6C_2\times ^7C_1$

The total no of ways of selecting 3 items out of 13 items is

$\Rightarrow ^{13}C_3$

Probability is

$\Rightarrow P=\dfrac{^6C_2\times ^7C_1}{^{13}C_3}=\dfrac{105}{286}\\\Rightarrow P=0.367$

6 0

2 years ago

D)) The ratio of the monthly income and expenditure of Sunayana is 5 : 3. If she

Gnom [1K]

Answer:

Sunayana's income is ₹25000 and expenditures are ₹15000.

Step-by-step explanation:

Let i denote the monthly income and e denote the expenditures.

We know that the ratio of the monthly income to expenditure is 5:3. So, we can write the following proportion:

$\frac{i}{e}=\frac{5}{3}$

Let's multiply both sides by e. This yields:

$i=\frac{5}{3}e$

We know that when the income is increased by 5000 and the expenditures are decreased by 3000, the new ratio is 5:2. So, we can write the following proportion:

$\frac{i+5000}{e-3000}=\frac{5}{2}$