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konstantin123 [22]
3 years ago
6

What is the distance between (8, -3)(4,−7)

Mathematics
1 answer:
mel-nik [20]3 years ago
5 0

Answer:

X and Y intercepts

The x-intercept is a point on the graph where y is zero

Using the equation we found in the previous step and substituting zero for y

y= -0.15x-2.77

0= -0.15x-2.77

0.15x= -2.77

x= -2.77/0.15 = -18.00

The x intercept for this straight line is -18.00

The y-intercept is a point on the graph where x is zero

Using the equation we found in the previous step and substituting zero for x

y= -0.15×0-2.77

y= -2.77

The y intercept for this straight line is -2.77

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Where is the picture to answer it?
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Nadia plans to paint her jewelry box. The box is shaped like a rectangular prism with the dimensions
Pachacha [2.7K]

Answer:

132\ in^{2} is closest to the total surface area of the box

Step-by-step explanation:

we know that

The surface area of the box is equal to

SA=2B+PH

where

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P is the perimeter of the base

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we have

L=7\frac{3}{4}\ in=\frac{7*4+3}{4}=\frac{31}{4}\ in

W=3\frac{1}{4}\ in=\frac{3*4+1}{4}=\frac{13}{4}\ in

H=3\frac{7}{8}\ in=\frac{3*8+7}{8}=\frac{31}{8}\ in

<em>Find the area of the base B</em>

B=LW

B=(\frac{31}{4})(\frac{13}{4})=\frac{403}{16}\ in^{2}

<em>Find the perimeter of the base P</em>

P=2(L+W)

P=2(\frac{31}{4}+\frac{13}{4}))

P=2(\frac{44}{4})=22\ in

<em>Find the surface area</em>

SA=2(\frac{403}{16})+22(\frac{31}{8})

SA=(\frac{403}{8})+(\frac{682}{8})

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6 0
3 years ago
Plz help with equation of the circle will award fastest CORRECT answer with brainliest
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Answer:

(x-1)^2+(y-2)^2=6.25

Step-by-step explanation:

The equation for a circle is given by:

(x-h)^2+(y-k)^2=r^2

Where (h,k) is the center and r is the radius.

The center is the red dot, which is (1,2). Thus, h=1 and k=2.

To find the radius, you need to use the distance formula. We are given two coordinates: the center (red dot) at (1,2) and a blue dot on the circle at (2.5,4). Find the radius by using the distance formula:

d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

Let (1,2) be <em>x₁ </em>and <em>y₁ </em>and let (2.5,4) be <em>x₂ </em>and <em>y₂. </em>Therefore:

d=\sqrt{(2.5-1)^2+(4-2)^2}\\d=\sqrt{(1.5)^2+2^2}\\d=\sqrt{2.25+4}\\d=\sqrt{6.25}=2.5

Thus, r is 2.5.

Plugging these numbers into the equation, we have:

(x-h)^2+(y-k)^2=r^2\\(x-1)^2+(y-2)^2=2.5^2\\(x-1)^2+(y-2)^2=6.25

3 0
3 years ago
What’s the domain and range of y=x^2+2
denpristay [2]

Answer:

domain: all real numbers

range: {y element R : y>=2}

Step-by-step explanation:

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