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Nezavi [6.7K]
3 years ago
6

Part of the population of 7000 oak in a wildlife preserve is infected with a parasite. A random sample of 50 elk shows that four

of them are infection. How many elks are infected?
Mathematics
1 answer:
lbvjy [14]3 years ago
7 0

Answer:

Answer is 560

Refer below.

Step-by-step explanation:

4/50=x/7000

50x=28000

X=560

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Please help me with Part C of this question!!!
anzhelika [568]

Answer:

  a. 3/4 inches per minute

  b. -1 1/8 inches per minute

  c. B is fastest; 1 1/8 is more than 3/4

Step-by-step explanation:

A <em>change</em> is a <em>difference</em>. A <em>rate of change</em> is <em>one difference divided by another</em>, usually the change in y-value divided by the change in x-value.

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<h3>a.</h3>

The change in elevation is the difference between the elevation at the end of the period (6 inches) and the elevation at the beginning of the period (3 inches). The change in time period is the difference between the end time (8 min) and the beginning time (4 min).

  change in elevation per minute = (6 -3 inches)/(8 -4 min)

  = (3 inches)/(4 min) = 3/4 inches/minute

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<h3>b.</h3>

Similarly, ...

  change in elevation per minute = (3 -7 1/2 inches)/(18 -14 min)

  = (-4 1/2 inches)/(4 min) = -1 1/8 inches/minute

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<h3>c.</h3>

We know that 3/4 is more than -1 1/8, but when we talk about the "fastest rate of change", we're generally interested in the magnitude--the value without the sign. That means we understand a rate of change of -1 1/8 inches per minute to be "faster" than a rate of change of 3/4 inches per minute.

The rate of change from Part B is fastest. 1 1/8 inches per minute is more than 3/4 inches per minute.

6 0
2 years ago
A survey of high school juniors found that 82% of students plan on attending college. If you pick three students at random, what
cupoosta [38]
<span> binomdist with n = 3, p = 0.82, q = 1-0.82 = 0.18
P[≥2] = P[2] + P[3] = 3c2 *0.82^2*0.18 + 0.82^3 ≈ 91%
hope it helps
</span>
6 0
3 years ago
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Ksivusya [100]

Answer:

Step-by-step explanation:

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19. \dfrac{a^{m}}{a^{n}}=a^{m-n}\\\\\\\dfrac{(-7p^{4})*(-8p^{5})}{2p^{3}}= \dfrac{(-7)*(-8)*p^{4}*p^{5}}{2p^{3}}\\\\\\=(-7)*(-4)*p^{4+5-3} \\\\= 28p^{6}\\

20)\dfrac{15a^{16}b^{11}}{(3a^{4}b^{2})^{3}}=\dfrac{15a^{16}b^{11}}{3^{3}*a^{4*3}*b^{2*3}}\\\\\\=\dfrac{15a^{16}b^{11}}{27*a^{12}*b^{6}}\\\\=\dfrac{5*a^{16-12}*b^{11-6}}{9}\\\\\\=\dfrac{5a^{4}b^{5}}{9}

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2 years ago
Express in simplest radical form.<br> V112<br> Answer:<br> Submit Answer
soldi70 [24.7K]
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3 years ago
Daniel is buying trophies and mounting stands for the upcoming basketball awards ceremony. The trophies come in boxes of 12 and
AveGali [126]

So, first, you have to find the smallest number that is divisible by both 12 and 10. Which is 60. So, you need 5 boxes of trophies and 6 boxes of stands

Now to get how much it will cost you now multiply the respective costs by the amount of boxes so you get

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Then you add both

50 + 36 = 86

He will spend a total of $86 on both trophies and stands.

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3 years ago
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