Answer:
<u>Direction open's Right </u>
Vertex: (0,0)
Focus: (5/4, 0)
axes of symmetry: y = 0
directrix: x = - 5/4
Step-by-step explanation:
Graph the parabola using the direction, vertex, focus, and axes of symmetry.
Hope this really helps u have good day :)
9514 1404 393
Answer:
1.63 cm (across the centerline from release)
Step-by-step explanation:
If we assume time starts counting when we release the weight from its fully-extended downward position, then the position at 1.15 seconds can be found from ...
h(t) = -7cos(2πt/4)
h(1.15) = -7cos(π·1.15/2) = -7(-0.233445) ≈ 1.63412 . . . cm
That is, 1.15 seconds after the weight is released from below the resting position, it will be 1.63 cm above the resting position.
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If it is released from <em>above</em> the resting position, it will be 1.63 cm <em>below</em> the resting position at t=1.15 seconds.
The points (0, 3) and (4, -1) are on the graph of y = -x + 3.
I have a site that I use a lot that is perfect for problems like these. It's called Desmos.com. It's basically a free online graphing calculator that is super helpful for most problems relating to graphs.
n can be 0 so 2(0) +3(0) = 0 now lets go up by one so 2(1) +3(1)= 5 now we will go up another number so lets go for 2(2)= 10 so we figured out that 2(1) +3(1) is 5 so n equals 1
2 + (3 - 9) / -3 * 4
1st is subtraction...u have to do what is in the parenthesis first
2 + (- 6) / -3 * 4
2nd is division
2 + 2 * 4
3rd is multiplication
2 + 8
4th is addition
10 <== ur solution
