The function is:
f ( x ) = x² - x - 72
This is a quatdratic function. So we can find the zeroes of the function with the formula:
x 1/2 = ( - b +/- √(b² - 4 ac) ) / ( 2a )
And we have: a = 1, b = - 1 and c = - 72
x 1/2 = ( 1 +/- √((-1)² - 4 · 1· ( - 72 )) ) / 2
x 1/2 = ( 1 +/- √( 1 + 288 ) ) / 2
x 1/2 = ( 1 +/- √289 ) / 2
x 1/2 = ( 1 +/- 17 ) / 2
x 1 = ( 1 - 17 ) 2 = - 16 / 2 = - 8
x 2 = ( 1 + 17 ) / 2 = 18 / 2 = 9
Answer: The zeroes are - 8 and 9.
Using your knowledge of place value the number is
12 6/10 which then reduces to
12 3/5
The radius of the cylinder before deformation is 7.5mm
<h3>Deformation of an object</h3>
From the given question, we are given that;
cold work radius of the cylinder is 10mm
Ductility = 25%
Determine the radius before deformation
Radius before deformation = (1- 0.5) + 10
Radius before deformation = 0.75 * 10
Radius before deformation = 7.5mm
Hence the radius of the cylinder before deformation is 7.5mm
Learn more on deformation here: brainly.com/question/6417346
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