Answer:
(2,0)
Step-by-step explanation:
For given line AB:
y-intercept = b = -2
slope = m = y₂-y₁/x₂-x₁
= -3/2-(-4) = -3/6 = -1/2
Equation of line AB:
y = (-1/2)x - 2
Finding equation of line that is parallel to line AB and passes through the point C(2,2):
Substituting the slope from line AB into the equation of the line
y = (-1/2)x + b.
Substituting the given point (-2,2) into the x and y values 2 = (-1/2)-2 + b.
Solving for b (the y-intercept)
, we get b = 1
Substitute this value for 'b' in the slope intercept form equation y = (-1/2)x + 1.
For x-intercept of the line, we let y = 0
0 = (-1/2)x + 1
x = -1(-2/1)
x = +2
So, the point on the x-axis that lies on the line that passes
through point C and is parallel to line AB is (2,0).
Answer:
y = x
Step-by-step explanation:
Slope-intercept form is the form that looks like
... y = mx + b . . . . . . for slope m and y-intercept b
The line connecting points D and E has slope 1 and y-intercept 0, so the equation is ...
... y = 1·x + 0
... y = x . . . . . . without the identity elements
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<em>Comment on the marked choice</em>
The choice that is marked is the equation in <em>point-slope form</em> using the point E (4, 4). That is not the form requested by the problem.
He difference between their sample means would likely stay the same.
I hope this help
Answer:
Evaluated, you get 4x^4
Step-by-step explanation:
Differentiated, you get 16x^3
It all depends on what you're looking for, really
Answer:
Below.
Step-by-step explanation:
It is a polynomial of degree 3.
