Just remove the parenthesis since you are adding them and combine like terms
x+5+2x+3
3x+8
the numbers are 6 and 13
let x be one of the numbers then the other is 2x + 1
their sum increased by 7 = 26
x + 2x + 1 + 7 = 26
3x + 8 = 26
subtract 8 from both sides
3x = 26 - 8 = 18
divide both sides by 3
x = 
= 6
the numbers are 6 and (2 × 6) + 1 = 12 + 1 = 13
Answer:
x = 3 + i+√5
x = 3 + i-√5
OR
x= 4 - √6
x= 4 +√6
Step-by-step explanation:
(x - 3)² +6=1
(x - 3)² + 6 = 1
-6 -6
sq root > (x - 3)² = -5
x-3 = i±√5 (i because neg. number)
x = 3 + i±√5
since its ±
two possible answers
x = 3 + i+√5
x = 3 + i-√5
Or
(x - 3)² +6=1
(x-3)+ √6= √ 1
x-3 = 1 - (±) √6
x= 4 - (±) √6
Answers
x= 4 - √6
x= 4 +√6
When the numerator are the same, which ever fraction's denominator is smaller is the larger number.
