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3 years ago

1. Given a regular octagon, find the measures of the angles formed by (a) two consecutive radii and (b) a

1 answer:

4 0

A ) The angle formed by 2 consecutive radii:
Ф= 360° : 8 = 45°
b ) The angle formed by a radius and a side of a polygon:
α = (180° - 45°): 2 = 135° : 2 = 67.5°
Answer:
B ) 45°, 67.5°

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Choose one <br> a. 7.8 ft<br> b. 8.8 ft<br> c. 8.3 ft<br> d. 9.2 ft

Scrat [10]

A =s^2 since the wall is square

78 =s^2

take the square root of each side

sqrt(78) = s

s=8.83 ft

Choice B

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3 years ago

Determine if given table represents a function. Explain

vichka [17]

Answer:

The table is not a function because of the same range and different domain values.

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3 years ago

Please help As Soon As Possible

vesna_86 [32]

Answer:

9.0 ft

Step-by-step explanation:

Let the distance from the bottom of the board to the edge of the wall be represented as "x"

Angle measure = θ = 53.13°

Hypotenuse = 15 ft

Adjacent side = x ft

The trigonometric ratio we would apply would be CAH:

Thus,

Cosine θ = Adjacent/Hypotenuse

Plug in the values

Cos 53.13° = x/15

Multiply both sides by 15

15 * Cos 53.13 = x

9.00002143 = x

x ≈ 9.0 ft (nearest tenth)

Therefore, distance from the bottom of the board to the edge of the wall = 9.0 ft

4 0

3 years ago

Over the last four years, the common stock of Plymouth Shippers has had an arithmetic average return of 10.4 percent. Three of t

brilliants [131]

Answer:

57.9

Step-by-step explanation:

8 0

3 years ago

Solve for x, y, and z

zloy xaker [14]

Answer:

The solution is x=1,y=2,z=3

Step-by-step explanation:

The given system of equations is ;\

2x−3y+4z=8...(1)

3x+4y−5z=−4...(2)

4x−5y+6z=12...(3)

Make x the subject in equation (1)

$x=\frac{8+3y-4z}{2}...(4)$

Put equation (4) into equation (2) and (3)

$3(\frac{8+3y-4z}{2})+4y-5z=-4$

Multiply through by;

$3(8+3y-4z)+8y-10z=-8$

Expand;

$24+9y-12z+8y-10z=-8$

Simplify;

$17y-22z=-32...(5)$

Equation (4) in (3)

$4(\frac{8+3y-4z}{2})-5y+6z=12$

$2(8+3y-4z)-5y+6z=12$

$16+6y-8z-5y+6z=12$

$y-2z=-4$

$y=2z-4...(6)$

Put equation (6) into equation (5)

$17(2z-4)-22z=-32$

$34z-68-22z=-32$

$34z-22z=-32+68$

$12z=36$

z=3

Put z=3 into equation (6)

y=2(3)-4=2

Put y=2 and z=3 into equation 4

$x=\frac{8+3(2)-4(3)}{2}=1$

The solution is x=1,y=2,z=3

3 0

3 years ago