Answer:
Step-by-step explanation:
Let x represent Dan's age
3x be James'age
Paul 2(3x+x)=6x+2x
Suming all ages
x+3x+6x+2x=120
Solving for x
12x=120
x=10 (Dan's age)
3×=30 (James'age)
6×+2×=80(Paul's age)
Answer:
1.(1,5) and (2,6) , 6-5/2-1=1/1 m=1 ,y=1x+b
5=1(1)+b 4=b
y=x+4
2.(1,1) and (3,-8) -8-1/3-1=-9/2 m=-9/2 ,y=-9/2x+b
1=-9/2(1)+b b=11/2
y=-9/x+11/2
3.(2.-3) and (5,-2) m=1/3 ,y=1/3x+b
-3=1/3(2)+b -3=2/3+b
-3-2/3=b
b=-11/3
y=1/3x-11/3
4.(2,5)and (4,3) m=-1 y=-1x+b
5=-1(2)+b 5=-2+b
5+2=b
b=7
y=-1x+7
6.(-3,-5) and (-1,-3) m=2/2=1 y=1x+b
-5=1(-3)+b -5=-3+b
-5+3=b
-2=b
y=1x-2
Step-by-step explanation:
Answer:
x/2 + 21 = 36
First we get rid of constants to isolate the variable.
In order to do that we must do the inverse operation.
Inverse operation of addition is subtraction.
-21 -21(subtracting 21 from both sides, whatever we do to the left side we do it to the right side too)
x/2 = 15
inverse property of division is multiplication
x2 x2
X = 30
The area of the rectangular is expressed in the formula A = l*w where l is the length and w is the width. from the first satement, l = 2 + w; then A = (2+w)*w = 2w + w^2. If A is equal to 168, then w should be equal to 12 feet and l is equal to 14 feet. Hence the width due to the border limits is 12- 2*2 equal to 8 feet