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Mice21 [21]
3 years ago
11

I need help on number 4

Mathematics
1 answer:
Ira Lisetskai [31]3 years ago
8 0

Answer:

√1,000,000 is the square root of 1,000 so √1,000,000=1,000

√36 is the square root of 6. So

√36=6

To check our work: 1,000•1,000 equals what? 1,000,000! So this is true.

For √36: what's 6•6? 36!! So this is also true.

We can also see the square roots for the other numbers are:

√3=1.73

√6=2.44

√100=10

√1000=31.62

So we match the right ones together which is √1,000,000=1,000 and √36=6

Hope this helps! If so please mark brainliest and rate/heart to help my account if it did!!

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Using the t-distribution, it is found that since the <u>test statistic is greater than the critical value for the right-tailed test</u>, it is found that there is enough evidence to conclude that Battery B outlasts Battery A by more than 2 hours.

At the null hypothesis, it is <u>tested if it does not outlast by more than 2 hours</u>, that is, the subtraction is not more than 2:

H_0: \mu_B - mu_A \leq 2

At the alternative hypothesis, it is <u>tested if it outlasts by more than 2 hours</u>, that is:

H_1: \mu_B - \mu_A > 2

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Hence, the standard errors are:

s_{Ea} = S_{Eb} = \frac{0.67}{\sqrt{12}} = 0.1934

The distribution of the difference has <u>mean and standard deviation</u> given by:

\overline{x} = \mu_B - \mu_A = 11.23 - 8.65 = 2.58

s = \sqrt{s_{Ea}^2 + s_{Eb}^2} = \sqrt{0.1934^2 + 0.1934^2} = 0.2735

The test statistic is given by:

t = \frac{\overline{x} - \mu}{s}

In which \mu = 2 is the value tested at the hypothesis.

Hence:

t = \frac{\overline{x} - \mu}{s}

t = \frac{2.58 - 2}{0.2735}

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Since the <u>test statistic is greater than the critical value for the right-tailed test</u>, it is found that there is enough evidence to conclude that Battery B outlasts Battery A by more than 2 hours.

A similar problem is given at brainly.com/question/13873630

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