Bettina’s age is three times Melvina’s age. If 20 is added to Melvina’s age and 20 is subtracted from Bettina’s age, their ages

Question

Mekhanik [1.2K]

3 years ago

11

Bettina’s age is three times Melvina’s age. If 20 is added to Melvina’s age and 20 is subtracted from Bettina’s age, their ages

will be equal. How old is each now?

Mathematics

2 answers:

koban [17] · Answer 1 · 2022-08-30T02:16:43+03:00

<span>Melvina's age is = x, Bettina's age is = 3x the equation is x + 20 = 3x - 20 subtract 3x from both sides -(3x) + x +20 = 3x - 20 - (3x) -2x + 20 = -20 subtract 20 from both sides -2x + 20 - (20) = -20 - (20) -2x = - 40 divide both sides by -2 (-2x)/-2 = (-40)/-2 x = 20 Melvinas age is 20 and Bettinas age is 60</span>

Deffense [45] · Answer 2 · 2022-08-30T04:00:19+03:00

Deffense [45]3 years ago

4 0

Answer:

bettina=60 melvina 20

Step-by-step explanation:

guess and check:) try it, it really works!