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Paul [167]
4 years ago
5

Please9a × 3 + 8a + 4 -11aPlease helpI'm confused​

Mathematics
2 answers:
DerKrebs [107]4 years ago
8 0

35a_11a+4

24a+4

hope it helps

marysya [2.9K]4 years ago
7 0

●✴︎✴︎✴︎✴︎✴︎✴︎✴︎✴︎❀✴︎✴︎✴︎✴︎✴︎✴︎✴︎✴︎✴︎●

Hi my lil bunny!

❧⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯☙

Let's simplify step-by-step.

9a * (3) + 8a + 4 -11a

= 27a + 8a + 4 + -11a

Combine Like Terms:

= 27a + 8a + 4 + -11a \\= ( 27a + 8a + -11a ) + (4) \\= 24a + 4

Answer : \boxed {24a + 4}

❧⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯☙

●✴︎✴︎✴︎✴︎✴︎✴︎✴︎✴︎❀✴︎✴︎✴︎✴︎✴︎✴︎✴︎✴︎✴︎●

Have a great day/night!

❀*May*❀

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Find p[b] in each case: (a) events a and b are a partition and p[a] = 3p[b]. (b) for events a and b, p[a ∪ b] = p[a] and p[a ∩ b
nirvana33 [79]

Answer:

Case(a): p[b]=\frac{1}{3}p[a]

Case(b): p[b]=0

Case(c):  p[b]=\frac{1}{2}p[a\cap b]

Step-by-step explanation:

Given

(a) events a and b are a partition and p[a] = 3p[b].

(b) for events a and b, p[a ∪ b] = p[a] and p[a ∩ b] = 0.

(c) for events a and b, p[a ∪ b] = p[a]− p[b].

we have to find the p[b] in each case:

Case (a): events a and b are a partition and p[a] = 3p[b].

gives p[b]=\frac{1}{3}p[a]

Case (b):  for events a and b, p[a ∪ b] = p[a] and p[a ∩ b] = 0.

p[a\cup b]=p[a] ⇒p[a]+p[b]-p[a\cap b]=p(a) ⇒ p[b]=0  ∵  p[a ∩ b] = 0.

Case(3):  for events a and b, p[a ∪ b] = p[a]− p[b].

p[a ∪ b] = p[a]− p[b]

⇒ p[a]+p[b]-p[a\cap b]=p[a]-p[b]

⇒ 2p[b]=p[a\cap b]

⇒  p[b]=\frac{1}{2}p[a\cap b]

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(1 - α)/2 = (1 - 0.95)/2 = 0.05 /2 = 0.025

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Alborosie

Answer:

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