<u>Answer</u>: B. Identify the source of the active connection
<em>Any problem can be fixed only finding of the source of it. We can fix a problem in ‘n’ number of ways but it might again come back if source of it is not identified.</em>
<u>Explanation:</u>
Identify the source of the active connection is the NEXT step the team should take. It is very similar to our human body.
If the infection is coming in the body again and again and gets fixed in the treatment, the reason for come - back will be identified so that it does not <em>lead to unnecessary treatment. </em>
In a similar way, if source are identified then the problem of come-back can be avoided. <em>So option B would be the right choice.</em>
A component which is most likely to allow both physical and virtual machines to communicate with each other is a: virtual switch.
<h3>What is virtualization?</h3>
Virtualization can be defined as the creation of an abstract layer over computer hardware primarily through the use of a software, in order to enable the operating system (OS), storage device, server, etc., to be used by end users over the Internet.
In Cloud computing, some of the components (features) which is not required for a successful virtualization environment include the following:
In conclusion, we can infer and logically deduce that a component which is most likely to allow both physical and virtual machines to communicate with each other is a virtual switch because it enables the virtual servers and the desktops to communicate.
Read more on virtualization here: brainly.com/question/14229248
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Complete Question:
Which component is most likely to allow physical and virtual machines to communicate with each other?
VHD.
Virtual switch.
Hyper V.
Host OS.
Answer:
(a) What is the best case time complexity of the algorithm (assuming n > 1)?
Answer: O(1)
(b) What is the worst case time complexity of the algorithm?
Answer: O(n^4)
Explanation:
(a) In the best case, the if condition will be true, the program will only run once and return so complexity of the algorithm is O(1)
.
(b) In the worst case, the program will run n^4 times so complexity of the algorithm is O(n^4).
Answer:
See the attached pictures for detailed answer.
Explanation:
The cache contain 8K number of blocks.each block has 16 Byte worth of data. Each of these bytes are addressable by block offset. Now, each of these blocks are addressable and their address is provided by line offset or set offset. If block number is given in Decimal format then the block to which that block will be mapped is given by expression
mappedToBlock = (bNumber)mod213
TAG and valid but consititues something called cache controller. TAG holds the physical address information because the TAG in physical address get divided into TAG and line offset in cache address. Valid bit tells status of blocks. If it is 1 then data blocks are referred by CPI else not.
