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For this case, the first thing to do is to observe that the figure is symmetrical with respect to the FH axis.
Therefore, the following lengths are the same:

So, by equalizing both sides we have:

From here, we clear the value of m.
We have then:


Answer:
The value of m is given by:

Answer:
A
Step-by-step explanation:
Answer:
The length of the rectangle is 18 cm
The width of the rectangle is 6 cm
Step-by-step explanation:
Let
x-----> the length of the rectangle
y----> the width of the rectangle
we know that
The perimeter of the rectangle is

we have

so
------> equation A
------> equation B
Substitute equation B in equation A and solve for y
48=2(2y+6+y)
48=2(3y+6)
48=6y+12
6y=48-12
y=36/6=6 cm
Find the value of x
x=2(6)+6=18 cm
The area of the rectangle is
A=xy
A=18*6
A=108 cm^2
The horizontal distance is the difference of x-coordinates: 6 - 4 = 2.
The vertical distance is the difference of y-coordinates: -1 - (-2) = 1.
The straight-line distance (d) can be found using the Pythagorean theorem, since the vertical and horizontal distances are at right angles to each other.
.. d² = 2² + 1² = 5
.. d = √5 ≈ 2.2
The distance UV is about 2.2.