The product of a <em>complex</em> number and its conjugate is (a + i b) · (a - i b), where a and b are <em>real</em> numbers, and the result for the <em>complex</em> number 2 + i 3 is 13.
<h3>What is the multiplication of a complex number and its conjugate</h3>
Let be a <em>complex</em> number a + i b, whose conjugate is a - i b. Where a and b are <em>real</em> numbers. The product of these two numbers is:
(a + i b) · (a - i b)
Then, we proceed to obtain the result by some algebraic handling:
a · (a + i b) + (- i b) · (a + i b)
a² + i a · b - i a · b - i² b²
a² - i² b²
a² + b²
If we know that a = 2 and b = 3, then the product of the complex number and its conjugate is:


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Answer:
D
Step-by-step explanation:
because we know that angle EOD is less the 90 so that means that it is complementary. For AOB it is the same but we can check by adding 35 plus x plus 90 =180 degrees so 35+90=125 x=180-125=55 so x=55 and 55 is less then 90 so it is a complementary angle.
Can u post a picture so I can better understand the question?
Explanation: more details.
Answer:
55 for the top left and 35 for the top right
Step-by-step explanation:
The sum of the angles of a triangle is 180 degrees
7x+6 + 6x -7 + 90 = 180
Combine like terms
13x+89 = 90
Subtract 89 from each side
13x+89-89 = 180-89
13x = 91
Divide by 13
13x/13 = 91/13
x =7
The top left angle is
7x+6
7*7+6 = 49+6 = 55
The top right angle is
6x-7
6*7-7 = 42-7 = 35