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Kamila [148]
3 years ago
8

_____ is the mature ovary of a flower. A. Conifer B. Angiosperm C. Cone D. Fruit

Biology
2 answers:
Whitepunk [10]3 years ago
8 0

The answer is D. Fruit because it is the seed-bearing structure

Anton [14]3 years ago
5 0

C.) Cone

A cone (in formal botanical usage: strobilus, plural strobili) is an organ on plants in the division Pinophyta (conifers) that contains the reproductive structures. The familiar woody cone is the female cone, which produces seeds. ... The individual plates of a cone are known as scales

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If a hamster has 22 chromosomes in its somatic cells, how many chromosomes would it have in its gametes
amm1812
Normally a hamster has 44 chromosome in its body but since it’s cut in half which leaves it 22 chromosomes (as stated above) the answer will be 11 gametes
22 divided by 2 = 11

EXPLANATION:
The sperm of the father, when it fuses with the egg, the embryo has 22 chromosomes
To find the number of chromosomes for each gamete, divide the total number by two eggs. The egg and sperm have half of the genetic information for an embryo
6 0
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Organize ten produce items fro the grocery store into a hierarchy, and make up a species name for each one based on Linnaean pri
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3 0
3 years ago
Hydrophilic head belongs to which group of organic molecules
telo118 [61]
That's a component of a phospholipid, which is a lipid.
5 0
3 years ago
Selective breeding has been used to make certain breeds of horses for the purpose of racing. Describe why you think people would
zhannawk [14.2K]
Some traits would be increased endurance, speed, strength, etc

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5 0
3 years ago
Day 1: 4 km Day 2: 10 km Day 3: 12 km Day 4: 12 km Day 5: 18 km Day 6: 24 km
yKpoI14uk [10]

Answer:

In order to find average speed during each interval, we need to divide the distance during those intervals with the period of time. So, for the first interval (day 0 to day 2) hawksbill started from 0 and reached 10 kilometers by the end of the second day. That means that it crossed 10 kilometers in 2 days, so the average speed is 10/2 which is 5 km/day. Similarly, we can calculate speed for other intervals:

• day 2 - day 3: it went from 10 to 12 km in one day, which means it crossed 2 km in one day, so the average speed is 2/1 = 2 km/day

• day 3 - day 4: at the end of the third day it reached 12 km and at the end of the day 4 it remained at 12 km. That means the hawksbill wasn't moving in that interval so the speed was 0

• day 4 - day 5: it went from 12 km to 18 km, which means it crossed 18-12=6 km in one day, so the average speed is 6/1=6 km/day

• day 5 - day 6: it went from 18 to 24 km, which means it crossed 24-18=6 km in one day, so the speed was 6/1=6 km/day

So, to summarize, during the first interval turtle was moving with average speed of 5 km/day, then 2 km/day, in the third interval it wasn't moving and in the last two intervals, it moved in average speed of 6 km/day.

6 0
3 years ago
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