Here, we are required to find the area of the paper board given after the semicircle is cut out of it
Area of the paper board thatremains is 423 in²
Length = 29 in
Width = 20 in
Area of a rectangle = length × width
= 29 in × 20 in
= 580 in²
Area of a semi circle = πr²/2
π = 3.14
r = diameter / 2 = 20 in / 2 = 10 in
Area of a semi circle = πr²/2
= 3.14 × (10 in)² / 2
= 3.14 × 100 in² / 2
= 314 in²/2
= 157 in²
The semicircle is cut out of the rectangle
Find the area of the paper board that remains after the semicircle is cut out of it by subtracting the area of a semi circle from the area of a rectangle
Area of the paper board that remains = Area of a rectangle - Area of a semi circle
= 580 in² - 157 in²
= 423 in²
brainly.com/question/16994941
Answer
63.2 degrees
Step-by-step explanation:
Using law of cosines: 19^2=8^2+14^2-2(8)(14) cos (x)
361=64+196-224 cos(x)
361=260-224cos(x)
101=224cos(x)
divide both sides by 224, which gets you (rounded to 4th decimal place) 0.4509. do inverse cos which gets you 63.2
Let n = the hours elapsed when the two trains are 660 miles apart.
Let the first train travel east and the second train travel west.
The distance traveled by the first train is
x = (50 mi/h)*(n h) = 50n mi
The distance traveled by the second train is
y = (60 mi/h)*(n h) = 60n h
The distance between the two trains after n hours is
x + y = 50 n + 60n = 110n mi
Because this distance is 660 miles, therefore
110n = 660
n = 6 hours
Answer: 6 hours
I hope this helps. Sorry it took so long
Answer
I believe the variable is a but I'm not 100% positive sorry
Answer:
234 in^2
Step-by-step explanation:
*look at the pick* 6+60+168=234
