Answer:
Correct integral, third graph
Step-by-step explanation:
Assuming that your answer was 'tan³(θ)/3 + C,' you have the right integral. We would have to solve for the integral using u-substitution. Let's start.
Given : ∫ tan²(θ)sec²(θ)dθ
Applying u-substitution : u = tan(θ),
=> ∫ u²du
Apply the power rule ' ∫ xᵃdx = x^(a+1)/a+1 ' : u^(2+1)/ 2+1
Substitute back u = tan(θ) : tan^2+1(θ)/2+1
Simplify : 1/3tan³(θ)
Hence the integral ' ∫ tan²(θ)sec²(θ)dθ ' = ' 1/3tan³(θ). ' Your solution was rewritten in a different format, but it was the same answer. Now let's move on to the graphing portion. The attachment represents F(θ). f(θ) is an upward facing parabola, so your graph will be the third one.
Answer:
Step-by-step explanation:
Sorry, I could do only the first three questions
The given equation is
x intercept
To find the x intercept, we have to plug 0 for y and solve for x.That is
So x intercept is (6,0) .
y intercept
To find the y intercept , we have to plug 0 for x and solve for y. That is
So the y intercept is (0,-9) .
Answer:
510-165=345.
Step-by-step explanation:
Well if you subtract 510-165 you would get 345. Therefore your answer would be " There are 345 marbles that are not in the jar."
Suppose width is X
then length would be X+44
perimeter of rectangle = 2 (length + width)
substitute:
328 = 2 ( X+44 + X )
328 = 2 ( 2X + 44 )
328 = 4X + 88
328 - 88 = 4X
240 = 4X
240/4 = X
X = 60
substitute in the first and second line
width is X so width = 60 feet
length is X + 44 = 60 + 44 = 104 feet
