Let the numbers be x = 5x+18
3(5x+18) + 4x= 16
15x+ 54+ 4x= 16
19x = 16-54
X=-38/19
X= -2
5x+18= 5 × -2+18 = 8
Yo has to factor since we assume that
if you have xy=0, x and y=0
7n^2-48n+36=0
trial and error
(7n-6)(n-6)=0
set each to zero
7n-6=0
add 6
7n=6
divide 7
n=6/7
n-6=0
add 6
n=6
n=6/7 or 6
It would be y=3x+2 because in y=mx+b, m is the slope and b is the y-intercept
Answer:
.
Step-by-step explanation: Given radical expression
.
According to the product property of roots.
![\sqrt[n]{a} \times \sqrt[n]{b} = \sqrt[n]{a \times b}](https://tex.z-dn.net/?f=%5Csqrt%5Bn%5D%7Ba%7D%20%5Ctimes%20%5Csqrt%5Bn%5D%7Bb%7D%20%3D%20%5Csqrt%5Bn%5D%7Ba%20%5Ctimes%20b%7D)
On applying above rule, we get
![\sqrt[3]{5x} \times \sqrt[3]{25x^2} = \sqrt[3]{5x \times 25x^2}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B5x%7D%20%5Ctimes%20%5Csqrt%5B3%5D%7B25x%5E2%7D%20%3D%20%5Csqrt%5B3%5D%7B5x%20%5Ctimes%2025x%5E2%7D)
5 × 25 = 125 and

Therefore,
![\sqrt[3]{5x \times 25x^2}= \sqrt[3]{125x^3}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B5x%20%5Ctimes%2025x%5E2%7D%3D%20%5Csqrt%5B3%5D%7B125x%5E3%7D)
<h3>So, the correct option would be second option
![\sqrt[3]{125x^3}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B125x%5E3%7D)
.</h3>