Solve 7x+y=50 4x+y=23 simultaneously
2 answers:
<em>so</em> <em> </em> <em>the</em> <em> </em> <em>valu</em> <em>e</em> <em> </em> <em>of</em> <em> </em> <em>x</em> <em> </em> <em>is</em> <em> </em> <em>9</em> <em> </em> <em>and</em> <em> </em> <em>y</em> <em> </em> <em>is</em> <em> </em> <em>-</em> <em>1</em> <em>3</em> <em>.</em>
<em>Hope</em> <em> </em> <em>this</em> <em> </em> <em>will</em> <em> </em> <em>help</em> <em> </em> <em>u</em> <em>.</em> <em>.</em> <em>.</em>
Answer:
x = 9 and y = -13
Step-by-step explanation:
7x + y =50.... eq 1
4x + y =23....eq 2
Subtract eq 2 from eq 1
7x + y = 50
-
4x + y = 23
This becomes;
7x - 4x + y - y= 50 -23
3x = 27
Divide both sides by the coefficient of x; 3
x = 9
Slot in the value of x in eq 1
7 (9) + y = 50
63 + y = 50
Subtract 63 from both sides
63 - 63 + y = 50 - 63
y = -13
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