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gavmur [86]
3 years ago
14

The first term of an Arithmetic Series is 6 and the third term is 12. What is the second term in the series?

Mathematics
1 answer:
Afina-wow [57]3 years ago
4 0

Answer:

18 I got it right

Step-by-step explanation:

on the test

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Convert base 10 273 to a base 12
Margaret [11]
The highest power of 12 that divides 273 (with remainder) is 12^2=144, and dividing gives

273=1(144)+129

Divide the remainder term by the next highest power of 12, 12^1=12.

129=10(12)+9

So 273_{10}=1a9_{12}, since

273=1\cdot144+10\cdot12+9\cdot1=1\cdot12^2+10\cdot12^1+9\cdot12^0
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Answer:

C

Step-by-step explanation:

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3 years ago
you are adding 3 2/3+2 2/3 using fraction strips explain how you rename the fraction part of the problem
garri49 [273]
We have to add 3 2/3 + 2 2/3 using fraction strips. 3 2/3 and 2 2/3 are the mixed numbers. The mixed numbers consists of a whole number and a fraction. If we want to add those numbers we shoukld change them into improper fractions: 3 2/3 = ( 3 * 3 + 2 ) / 3 = 11 / 3; 2 2/3 = ( 2 * 3 + 2 ) / 2 = 8 / 3. Finally: 11 / 3 + 8 / 3 = ( 11 + 8 ) / 3 = 20 / 3 = 6 2/3. Answer: You reneme it turning them into improper fractions<span>. </span>
4 0
3 years ago
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