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Step2247 [10]
3 years ago
10

The geek dormitory has 75 rooms numbered 0 to 74. each student is assigned a room whose number is the student's id number modulo

75. how many students must there be to be certain that at least 2 students will be sharing a room?
Mathematics
2 answers:
Basile [38]3 years ago
5 0
Their should be at least 150 students

ozzi3 years ago
4 0

Answer:

at least 150 students.

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Which expression has a value of -6 A. -4 • 2 - (-14) B. -16 divided by (-2) - (-2) C. -2 - (-8) divided by (-1) D. -12 divided b
tatiyna

Answer:

its B. -16 divided by (-2) - (-2)

8 0
3 years ago
Tessa had $90 in her checking account. She paid her cable/internet bill for $60. She deposited $50 from her part-time job before
Lady bird [3.3K]

90-60+50-65=15


$15 in her account

4 0
3 years ago
Read 2 more answers
Determine whether each given value of x satisfies the inequality x+1<x/3
Vinil7 [7]

x+1 < \dfrac{x}{3}\ \ \ \ |\cdot3\\\\3x+3 < x\ \ \ \ |-3\\\\3x < x-3\ \ \ \ |-x\\\\2x < -3\ \ \ \ |:2\\\\x < -1.5

Answer: (c) x = -4

5 0
3 years ago
What is the answer to the equation 5x=2x+20?
Agata [3.3K]

I don't know.  But I know how to find it.  Let's work it out together:

                                              <u>5x  =  2x + 20</u>

Subtract  2x  from each side:    3x  =  20

Divide each side by  3 :              <em>x  =  20/3</em>  or    ( 6 and 2/3 ).


3 0
3 years ago
Read 2 more answers
A bag contains different colored candies. There are 50 candies in the bag, 28 are red, 10 are blue, 8 are green and 4 are yellow
Mrrafil [7]

Answer:

\displaystyle \frac{54}{5405}.

Step-by-step explanation:

How many unique combinations are possible in total?

This question takes 5 objects randomly out of a bag of 50 objects. The order in which these objects come out doesn't matter. Therefore, the number of unique choices possible will the sames as the combination

\displaystyle \left(50\atop 5\right) = 2,118,760.

How many out of that 2,118,760 combinations will satisfy the request?

Number of ways to choose 2 red candies out a batch of 28:

\displaystyle \left( 28\atop 2\right) = 378.

Number of ways to choose 3 green candies out of a batch of 8:

\displaystyle \left(8\atop 3\right)=56.

However, choosing two red candies out of a batch of 28 red candies does not influence the number of ways of choosing three green candies out of a batch of 8 green candies. The number of ways of choosing 2 red candies and 3 green candies will be the product of the two numbers of ways of choosing

\displaystyle \left( 28\atop 2\right) \cdot \left(8\atop 3\right) = 378\times 56 = 21,168.

The probability that the 5 candies chosen out of the 50 contain 2 red and 3 green will be:

\displaystyle \frac{21,168}{2,118,760} = \frac{54}{5405}.

3 0
3 years ago
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