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galina1969 [7]
3 years ago
13

Complete the function remove_all(L, x) so that, given a list L and a target value x, it returns a copy of the list that excludes

all occurrences of x but preserves the order of the remaining elements.

Mathematics
1 answer:
tia_tia [17]3 years ago
4 0

Answer:

Code is given below along with explanation and output.

Step-by-step explanation:

we can use the method of list comprehension to achieve the given task.

In a list comprehension, we create a sub-list of elements which satisfy specific conditions. the condition i !=x makes sure that x would be excluded in the modified list.

def remove_all(L, x):

   return [i for i in L if i != x]

L = [1, 2, 3, 4, 5, 6, 4, 3, 2, 4 ]

print('Before =',L)

L = remove_all(L, 4)

print('After =',L)

Output:

Before = [1, 2, 3, 4, 5, 6, 4, 3, 2, 4]

After = [1, 2, 3, 5, 6, 3, 2]

As you can see we have successfully removed the multiple occurrence of x=4 while preserving the order of the list.

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