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strojnjashka [21]
3 years ago
6

In May, Bradley bought 48 styrofoam balls and decorated them as toy figurines. In June, he sold 19 figurines. In May, Lupe bough

t 44 styrofoam balls to decorate, and in June, she sold 21 figurines. Make a matrix that represents all of their May purchases and their June sales? .
Mathematics
2 answers:
mafiozo [28]3 years ago
7 0

Answer:

Step-by-step explanation:

Since we have given that

Number of styrofoam balls bought by Bradley in May = 48

Number of toy figurines sold in May = 19

Number of styrofoam balls bought by Lupe in June = 44

Number  of toy figurines sold in June = 21

So, we need to make a matrix that represents all of their May purchases and their June sales :

So, it is given by

                       May                    June

                    Purchases             Sales     

 Bradley       48                            19

 Lupe            49                           21

Thus, we can define a 2x2 matrix in which row 1 represents Bradley and row 2 represents Lupe. The columns then represent May and June. To distinguish between purchase and sale, we will show sale by a positive number and sale with negative; therefore the final matrix will be

\left[\begin{array}{ccc}48-19\\44-21\end{array}\right]

vitfil [10]3 years ago
4 0

Step-by-step explanation:

Since we have given that

Number of styrofoam balls bought in May = 48

Number of toy figurines sold in May = 19

Number of styrofoam balls bought in June = 44

Number  of toy figurines sold in June = 21

So, we need to make a matrix that represents all of their May purchases and their June sales :

So, it is given by

                        May                    June

                     Purchases             Sales     

 Bradley      48                            19

 Lupe           49                           21

Hence, the proper matrix will be

\begin{bmatrix}48 &19 \\ 49&22 \end{bmatrix}

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