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3 years ago

On Thursday evening Malcolm's bank balance was −£107.35.

Mathematics

1 answer:

Sloan [31]3 years ago

8 0

-107.35 + 1,867.68 = 1,760.33

1,760.33 - 715.21 = 1,045.12

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Please help! Find the area and the perimeter of the shaded regions below. Give your answer as a completely simplified exact valu

Nadya [2.5K]

Answer:

$The \ area \ of \ the \ figure = 4\dfrac{1}{2} \cdot \pi + 18 \ cm^2$

Step-by-step explanation:

Given that the figure is made up of portion of a square and a semicircle, we have;

BC ≅ AB = 6 cm

The area of semicircle BC with radius BC/2 = 3 is 1/2×π×r² = 1/2×π×3² = 4.5·π cm²

Triangle ABC = 1/2 × Area of square from which ABC is cut

The area of triangle ABC = 1/2×Base ×Height = 1/2×AB×BC = 1/2×6×6 = 18 cm²

The area of the figure = The area of semicircle BC + The area of triangle ABC

The area of the figure = 4.5·π cm² + 18 cm² = $\dfrac{9 \cdot \pi +36}{2} \ cm^2$ .

5 0

3 years ago

NEED HELP ASAP <br> WILL GIVE BRAIN

34kurt

Im really dumb i srry!

7 0

3 years ago

Reflect each point in the x-axis and y-axis

Vilka [71]

Step-by-step explanation:

1. x: (-12, -13) y: (12, 13)

2. x: (4 ,9) y: (-4, -9)

3. x: (-10, 8) y: (10, -8)

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3 years ago

Read 2 more answers

2(x - 2.6) + 2.91 = 7.71

Gennadij [26K]

I'll show a step-by-step. I'm not in the mood to explain right now lol.

2(x-2.6)+2.91=7.71

2x-5.2+2.91=7.71

+5.20 +5.20

2x+2.91=12.91

-2.91 -2.91

2x=10

/2 /2

x=5

---

hope it helps

sorry if it doesn't

3 0

3 years ago

30 years ago zoe was 2/3 as old as luke, 18 years ago zoe was 5/6 as old as luke how old are they now

barxatty [35]

Based on the mathematical statements, Zoe is 56 years old and Luke is 66 years old, now

<h3>How to determine how old they are now?</h3>

From the question, we have the following statements that can be used in our computation:

<u>30 years ago</u>

Zoe was 2/3 as old as Luke

<u>18 years ago</u>

Zoe was 5/6 as old as Luke

Let their present ages be represented as

Zoe = x

Luke = y

So, we have the following representations

<u>30 years ago</u>

Zoe was 2/3 as old as Luke

x - 36 = 2/3(y - 36)

<u>18 years ago</u>

Zoe was 5/6 as old as Luke

x - 18 = 5/6(y - 18)

So, we have the following system of equations

x - 36 = 2/3(y - 36)

x - 18 = 5/6(y - 18)

Make x the subject in x - 18 = 5/6(y - 18)

x = 5/6(y - 18) + 16

Substitute x = 5/6(y - 18) + 16 in x - 36 = 2/3(y - 36)

5/6(y - 18) + 16 - 36 = 2/3(y - 36)

Open the brackets

5/6y - 15 + 16 - 36 = 2/3y - 24

Evaluate the like terms

5/6y - 35 = 2/3y - 24

Multiply through by 6

5y - 210 = 4y - 144

Evaluate the like terms

y = 66

Substitute y = 66 in x = 5/6(y - 18) + 16

x = 5/6(66 - 18) + 16

Evaluate

x = 56

Recall that

Zoe = x

Luke = y

So, we have

Zoe = x = 56

Luke = y = 66

Hence, they are 56 and 66 years, now