(x+6)^(1/2)-5=x+1
(x+6)^(1/2)=x+6
((x+6)^(1/2))^2=(x+6)^2
x+6=x^2+12x+36
0=x^2+11x+30
(-11+(11^2-4(1)(30))^(1/2))/2
(-11+((1)^(1/2))/2
(-11+1)/2=-5
(-11-1)/2=-6
((-6)+6)^1/2-5=(-6)+1
(0^(1/2))-5=-5
-6 is non-extraneous
((-5)+6)^1/2-5=(-5)+1
(1^1/2)-5=-4
1-5=-4
-4=-4
-5 is non-extraneous
As we have to solve for b, it means we have to isolate b
So first of all subtract 
from both sides
So we get
Now we need b , but its b^2 , so we can take square root on both sides.
taking square roots on both sides
Hence option B is correct
Answer:
H is the reflection of itself in the horizontal line
Divide the price by the quantity:
Bananas = 5.40 / 6 = 0.90 each
Oranges = 2.56/8 = 0.32 each
Apples = 4.68 / 12 = 0.39 each
Mangos = 3.16 / 4 = 0.79 each
Oranges have the lowest price each so are the best buy.
The domain is the x-axis and the range is the y-axis.
So the range of the function would be the Y values given.
So the range would be (3, 6, 9, 12, 15).
