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Nezavi [6.7K]
2 years ago
8

Please answer I really need help with these just answer at least one.

Mathematics
1 answer:
aleksandrvk [35]2 years ago
7 0
.50(150)+30=$105
8(32)+12 = $268
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HELP ME BEFORE I DIE!
KonstantinChe [14]

Answer:

0.6 or \frac{3}{5}

Step-by-step explanation:

Using the Pythagorean theorem (a^{2} +b^{2} =c^{2}) we get that the hypotenuse is 5.

so the cos V is adjacent over the hypotenuse. so if adjacent is 3 and hypotenuse is 5, the answer is \frac{3}{5} which equals 0.6 in decimal form.

3 0
3 years ago
Suppose you invest 16000 at 9% interest and that it is compounded daily. How much will you have in 8 years?
forsale [732]

Answer:

Compound interest is calculated by multiplying the initial principal amount by one plus the annual interest rate raised to the number of compound periods minus one.

Step-by-step explanation:

5 0
3 years ago
What is the area of this parallelogram?<br><br><br> 104 m²<br><br> 88 m²<br><br> 56 m²<br><br> 32 m²
iragen [17]

Answer: To find area of a rectangle, multiply its base (length) by its height (width). Plug in the base, 7 meters, and the height, 8 meters. So the area of Rectangle DFBE is 56 square meters.

88m

HOPE THIS HELPS

6 0
3 years ago
If you wish to warm 40 kg of water by 18 ∘C for your bath, find what the quantity of heat is needed. Express your answer in calo
Harman [31]

Answer:

Quantity of heat needed (Q) = 722.753 × 10³

Step-by-step explanation:

According to question,

Mass of water (m) = 40 kg

Change in temperature ( ΔT) = 18°c

specific heat capacity of water = 4200 j kg^-1 k^-1

The specific heat capacity is the amount of heat required to change the temperature of 1 kg of substance to 1 degree celcius or 1 kelvin .

So, Heat (Q) = m×s×ΔT

Or,          Q = 40 kg × 4200 × 18

or,           Q = 3024 × 10³ joule

Hence, Quantity of heat needed (Q) = 3024 × 10³ joule    

In calories 4.184 joule = 1 calorie

So, 3024 × 10³ joule = 722.753 × 10³

6 0
3 years ago
Find the volume of a cylinder that has a diameter of 6 and a height of 9. Leave your answer in terms for pi.
Gekata [30.6K]

the volume maybe is 1017.88

6 0
2 years ago
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