Graph −7y+8=21x−6 .

Suppose a certain manufacturing company produces connecting rods for 4- and 6-cylinder automobile engines using the same product

gregori [183]

Answer:

Generally the constraint that sets next week are shown below

Generally the constrain that sets next week maximum production of connecting rod for 4 cylinder to W_4 or 0 is

$x_4 \le W_4 * s_4$

$x_4 \le 5000 * s_4$

Generally the constrain that sets next week maximum production of connecting rod for 6 cylinder to W_6 or 0 is

$x_6 \le W_6 * s_6$

$x_6 \le 8,000 * s_6$

Generally the constrain that limits the production of connecting rods for both 4 cylinder and 6 cylinders is

$x_4 \le W_4 * s_6$

=> $x_4 \le 5000 * s_6$

$x_4 \le W_6 * s_4$

=> $x_4 \le 8000 * s_4$

$s_4 + s_6 = 1$

The minimum cost of production for next week is

$U = M_4 * x_4 + M_6 * x_6 + C_4 * s_4 + C_6 * s_6$

=> $U = 13x_4 + 16x_6 + 2000 s_4 + 3500 s_6$

Step-by-step explanation:

The cost for the four cylinder production line is $C_4 = \$2,100$

The cost for the six cylinder production line is $C_6 = \$3,500$

The manufacturing cost for each four cylinder is $M_4= \$13$

The manufacturing cost for each six cylinder is $M_6= \$16$

The weekly production capacity for 4 cylinder connecting rod is $W_4 = 5,000$

The weekly production capacity for 6 cylinder connecting rod is $W_6 = 8,000$

Generally the constraint that sets next week are shown below

Generally the constrain that sets next week maximum production of connecting rod for 4 cylinder to W_4 or 0 is

$x_4 \le W_4 * s_4$

$x_4 \le 5000 * s_4$

Generally the constrain that sets next week maximum production of connecting rod for 6 cylinder to W_6 or 0 is

$x_6 \le W_6 * s_6$

$x_6 \le 8,000 * s_6$

Generally the constrain that limits the production of connecting rods for both 4 cylinder and 6 cylinders is

$x_4 \le W_4 * s_6$

=> $x_4 \le 5000 * s_6$

$x_4 \le W_6 * s_4$

=> $x_4 \le 8000 * s_4$

$s_4 + s_6 = 1$

The minimum cost of production for next week is

$U = M_4 * x_4 + M_6 * x_6 + C_4 * s_4 + C_6 * s_6$

=> $U = 13x_4 + 16x_6 + 2000 s_4 + 3500 s_6$

3 0

3 years ago

Please help me I’m very bad at math and I’m goibn thru it

vodomira [7]

The answer is in the picture provided below. :)

5 0

3 years ago

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Solve for x: 3(x 1)=-2(x-1)-4

prohojiy [21]

Solve the rational equation by combining expressions and isolating the variable x.

x=/ $-\frac{2}{5}$ 5

4 0

3 years ago

ANSWER BOTH QUESTION FOR BRAINLIST

Mrrafil [7]

Answers:

#4= 5

#5= +3

#4 Jake of ratio is: 3:15

2:10

5:25

So 25/5 or 10/2 or 15/3 they all get the same result which is 5

#5 The pattern of the X is 0, 1, 2, 3...

The pattern of the Y is 3, 6, 9, 12...

The pattern of Y would be adding 3.

+3

3 0

3 years ago

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What are the solutions of the inequality h-2>2?

strojnjashka [21]

Answer:

h > 4

Step-by-step explanation:

h -2 >2

add two to the other side

3 0

3 years ago

Graph ​ −7y+8=21x−6 ​.

Graph −7y+8=21x−6 .