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3 years ago

11

How to find the first quartile

2 answers:

givi [52]3 years ago

5 0

Answer:

The first quartile, denoted by Q1 , is the median of the lower half of the data set. This means that about 25% of the numbers in the data set lie below Q1 and about 75% lie above Q1 . The third quartile, denoted by Q3 , is the median of the upper half of the data set.

Step-by-step explanation:

jeyben [28]3 years ago

4 0

Q1= the median of the lower half of the datas

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Liam and Harper are racing on a track. Liam runs 4 miles per hour and gets a 0.25 miles head start. Harper runs 0.5 mile per hou

igomit [66]

S=d/t
for liam
4=.25/t
t=.25/4
t=0.0625hours
for harper
t=0.25/4.5=0.055hours
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3 years ago

Determine the value of w and x in the figure below. (Thanks for the help I really appreciate it!)

storchak [24]

Triangle HAM looks like an isosceles triangle, and we know that in an isosceles triangle 2 of the angles are the same.

so :
180 - 106 = 74 ( sum of the other 2 angles )
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3 years ago

Ivan used coordinate geometry to prove that quadrilateral EFGH is a square.

Gelneren [198K]

Answer:

(A)Segment EF, segment FG, segment GH, and segment EH are congruent

Step-by-step explanation:

<u>Step 1</u>

Quadrilateral EFGH with points E(-2,3), F(1,6), G(4,3), H(1,0)

<u>Step 2</u>

Using the distance formula

$Distance=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Given E(-2,3), F(1,6)

$|EF|=\sqrt{(6-3)^2+(1-(-2))^2}=\sqrt{3^2+3^2}=\sqrt{18}=3\sqrt{2}$

Given F(1,6), G(4,3)

$|FG|=\sqrt{(3-6)^2+(4-1)^2}=\sqrt{3^2+3^2}=\sqrt{18}=3\sqrt{2}$

Given G(4,3), H(1,0)

$|GH|=\sqrt{(0-3)^2+(1-4)^2}=\sqrt{(-3)^2+(-3)^2}=\sqrt{18}=3\sqrt{2}$

Given E (−2, 3), H (1, 0)

$|EH|=\sqrt{(0-3)^2+(1-(-2))^2}=\sqrt{(-3)^2+(3)^2}=\sqrt{18}=3\sqrt{2}$

<u>Step 3</u>

Segment EF ,E (−2, 3), F (1, 6)

Slope of |EF|= $\frac{6-3}{1+2} =\frac{3}{3}=1$

Segment GH, G (4, 3), H (1, 0)

Slope of |GH| $= \frac{0-3}{1-4} =\frac{-3}{-3}=1$

<u>Step 4</u>

Segment EH, E(−2, 3), H (1, 0)

Slope of |EH| $= \frac{0-3}{1+2} =\frac{-3}{3}=-1$

Segment FG, F (1, 6,) G (4, 3)

Slope of |EH| $=\frac{3-6}{4-1} =\frac{-3}{3}=-1$

<u>Step 5</u>

Segment EF and segment GH are perpendicular to segment FG.

The slope of segment EF and segment GH is 1. The slope of segment FG is −1.

<u>Step 6</u>

<u>Segment EF, segment FG, segment GH, and segment EH are congruent. </u>

The slope of segment FG and segment EH is −1. The slope of segment GH is 1.

<u>Step 7</u>

All sides are congruent, opposite sides are parallel, and adjacent sides are perpendicular. Quadrilateral EFGH is a square

4 0

3 years ago

Read 2 more answers

suppose a population of 250 crickets doubles in size every six months. How many crickets will there be after two years?

lord [1]

double every 6 months

in 6 months there would be 250*2 = 500 crickets

in 1 year there would be 500*2 = 1000 crickets

in 1.5 years there would be 1000 *2 = 2000 crickets

in 2 years there would be 2000 *2 = 4000 crickets

4 0

3 years ago

Suppose that y varies inversely with x. Use the information to find k, and then choose the equation of variation. x = 2 when y =

Sergeeva-Olga [200]

Answer:

y = $\frac{22}{x}$

Step-by-step explanation:

given that y varies inversely with x then the equation relating them is

y = $\frac{k}{x}$ ← k is the constant of variation

To find k use the condition x = 2 when y = 11

k = yx = 11 × 2 = 22

y = $\frac{22}{x}$ ← equation of variation

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3 years ago

Read 2 more answers