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lbvjy [14]
4 years ago
10

I don't know what to do

Mathematics
2 answers:
Debora [2.8K]4 years ago
7 0
This is easy go on khan academy an look up how to find the y coordinate
andrew-mc [135]4 years ago
4 0
Just make Y the subject of the equations (y=mx+c) where m is the gradient and c is the y-intercept (when x=0) and continue from there
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Simplify the expression −2(14−54a)
Natasha2012 [34]

Answer:

108a−28

Step-by-step explanation:

6 0
3 years ago
You are planning to make an open rectangular box from a 24​-in.-by-47​-in. piece of cardboard by cutting congruent squares from
miskamm [114]

Answer:

The dimensions are  13.92inches by 36.92inches by 5.04inches

Volume is 2590.18 inches³

Step-by-step explanation:

see attachment for the figure

supposing 'h' is side length of the square and also the height of the box

then, According to the question

Length of the box 'L'= 47 - 2h

Width of the box 'w'= 24 - 2h

Volume of the box 'V'= hLw

Substituting the values of 'L' and 'w' in above equation

V= h(47 - 2h)(24 - 2h)

V=(47h - 2h²)(24 - 2h) => 1128h - 94h²-48h²+4h³

V= 4h³ -142h²+1128h -->eq(1)

Taking derivative on both sides.

V' = 12h² - 284h + 1128

Setting the equation to zero, we will have

0=12h² - 284h + 1128

0= 3h² - 71h + 282

Using Quadratic formula to find h

h=  (-b+-√b²-4ac) / 2a

  = 71+-√71² - (4 x 3 x 282) / (2 x 3)=> 71+-√5041- 3384 / 6

h  =(71+- 40.706)/ 6

EITHER h= 18.6

OR h=5.04

By substituting the value of 'h' in eq(1)

(1)=>V(18.6)= 4(18.6)³ -142(18.6)²+1128(18.6) => -2406.096

(1)=>V(5.04)= 4(5.04)³ -142(5.04)²+1128(5.04) => 2590.18

By ignoring the negative value, we will have h=5.04

Therefore,

L= 47 - 2h => 47 -2(5.04) =>36.92

w= 24 - 2h=> 24- 2(5.04)=> 13.92

The dimensions are  13.92inches x 36.92inches x 5.04inches

Volume is 2590.18 inches³

7 0
4 years ago
Boat A is 20 km from port on a bearing of 025° and boat B is 25 km from port on a bearing of 070°. Boat B is in distress. What b
tiny-mole [99]

Answer: Boat A should travel 152.8° to reach B

Step-by-step explanation:

The diagram illustrating the scenario is shown in the attached photo. Triangle ABP is formed. A represents the position of boat A. B represents the position of boat B. P represents the position of the port.

We would determine AB by applying the law of cosines

AB² = AP² + BP² - 2AP×BPCosP

AB² = 20² + 25² - 2 × 20 × 25 × Cos45

AB² = 1025 - 707.10678 = 317.89322

AB = √317.89322 = 17.83

We would determine the bearing of B from A by finding angle A. We would apply the sine rule.

AB/SinP = AP/Sin A

17.83/Sin45 = 20/SinA

Cross multiplying, it becomes

17.83 × SinA = 20Sin45 = 14.14

SinA = 14.14/17.83 = 0.79

A = Sin^-1(0.79) = 52.2°

The total angle at A is 65 + 52.2 = 117.2°

The angle formed outside the third quadrant is 117.2 - 90 = 27.2°

Therefore, bearing B from A is

180 - 27/2 = 152.8°

3 0
3 years ago
Find the value of this expression if x = 5.<br> x2 + 2<br> x+4
denis-greek [22]

Answer:

If x=5, the solution would be 3.

5 0
4 years ago
Read 2 more answers
Graph f(x)=log 1/2 (x+1)
iVinArrow [24]

Please keep in mind that f(x)=log 1/2 (x+1) can also be written as:

f(x)=log ((x+1)/2)

6 0
4 years ago
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