Answer: Ox=3,y=11 Ox
Step-by-step explanation:
Answer:
14 and 16
Step-by-step explanation:
your adding 2 to each each time, if your looking for the multiplied awnser its 224
P(B) = 8/12
P(R | B) = 4/11
P(B ∩ R) = 8/33
The probability that the first ball chosen is black and the second ball chosen is red is about 24% percent
<em><u>Solution:</u></em>
<em><u>The probability is given as:</u></em>

Given that,
A box contains four red balls and eight black balls
Red = 4
Black = 8
Total number of possible outcomes = 12
Let event B be choosing a black ball first and event R be choosing a red ball second.
<h3><u>Find P(B)</u></h3>

<h3><u>Find P(B n R)</u></h3>

<h3><u>Find </u><u>
P(R | B)</u></h3><h3>

</h3>
<em><u>The probability that the first ball chosen is black and the second ball chosen is red is about percent</u></em>

Thus the probability that the first ball chosen is black and the second ball chosen is red is about 24% percent
Answer:
54
Step-by-step explanation:
12+(8)4-6
12+48-6
60-6
54
Answer:
10
Step-by-step explanation:
The constant of variation would be 12 / 1.2 = 10.