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Furkat [3]
2 years ago
6

Find the solution to the system of equations: 7x-8y=-23 7x-7y=-14

Mathematics
1 answer:
Vinil7 [7]2 years ago
4 0

Answer:

Solutions: x = 7, y = 9;  or (7, 9)

Step-by-step explanation:

Given the following systems of linear equations:

7x - 8y = -23

7x - 7y = -14

Since the coefficients of x in the given system have the same sign, we could use the process of elimination by subtracting the two equations.

    7x - 8y = -23

<u> -   7x - 7y = -14     </u>

             -y = -9  

Divide both sides by -1 to solve for y:

\frac{-y}{-1} =  \frac{-9}{-1}

y = 9

Substitute the value of y into either one of the given equations to solve for x:

7x - 7y = -14

7x - 7(9) = -14

7x - 63 = -14

Add 63 to both sides:

7x - 63 + 63 = -14 + 63

7x = 49

Divide both sides by 7 to solve for x:

\frac{7x}{7} = \frac{49}{7}

x = 7

Double-check whether x = 7 and y = 9 are valid solutions to the given system:

x = 7, y = 9:

<h3>7x - 8y = -23</h3>

7(7) - 8(9) = -23

49 - 72 = -23

-23 = -23 (True statement).

<h3>7x - 7y = -14</h3>

7(7) - 7(9) = -14

49 - 63 = -14

-14 = -14 (True statement).

Therefore, the solution to the given systems of linear equations are x = 7, and y = 9, or (7, 9).

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3 0
3 years ago
From the parking lot at red hill shopping center the angle of the top of the hill is about 25 from the base of the hill the angl
eimsori [14]

Answer:

512 ft.

Step-by-step explanation:

From the parking lot at the Red Hill Shopping Center, the angle of sight (elevation) to the top of the hill is about 25. From the base of the hill you can also sight the top but at an angle of 55. The horizontal distance between sightings is 740 feet. How high is Red Hill? Show your subproblems.

Solution:

Let x be the distance from the base of the hill to the middle of the hill perpendicular to the height, let h be the height of the hill. Therefore:

tan 25 = h/(x + 740)

h = (x + 740)tan 25       (1)

tan 55 = h / x

h = x tan 55        (2)

Hence:

(x + 740)tan 25 = xtan 55

0.4663(x + 740) = 1.428x

0.4663x + 345.07 = 1.428x

0.9617x = 345.07

x = 359 ft.

h = xtan55 = 359 tan(55) = 512 ft.

8 0
2 years ago
When a constant force is applied to an object, the acceleration of the object varies inversely with its mass. When a certain con
marusya05 [52]

Answer: The mass of the object is 10 kg

Step-by-step explanation:

According to Newton's second law of motion, the force F applied to an object with mass m is directly proportional to its acceleration a:

F=ma (1)

If we isolate a:

a=\frac{F}{m} (2) This means the acceleration of the object varies inversely with its mass

Now, we are given the following data to calculate a constant force using (1):

m_{1}=4 kg

a_{1}=5 m/s^{2}

F=m_{1}a_{1} (3)

F=(4 kg)(5 m/s^{2) (4)

F=20 N (5)

If we apply this same force calulated in (4) in another object with an acceleration of a_{2}=2 m/s^{2}, its mass m_{2} will be:

F=m_{2}a_{2} (6)

20 N=m_{2}2 m/s^{2} (7)

Finding  m_{2}:

m_{2}=10 kg This is the mass of the object

4 0
3 years ago
Vectorcardiography Suppose the voltage vector of a healthy heart is given by [0.3, 20.2]. Cardiac abnormalities result in change
Alexeev081 [22]

Answer:

Please see attachment

Step-by-step explanation:

Please see attachment

7 0
3 years ago
Given right triangle jkl, what is the value of cos(l)? five-thirteenths five-twelfths twelve-thirteenths twelve-fifths
kykrilka [37]

The value of the cosine ratio cos(L) is 5/13

<h3>How to determine the cosine ratio?</h3>

The complete question is added as an attachment


Start by calculating the hypotenuse (h) using

h^2 = 5^2 + 12^2

Evaluate the exponent

h^2 = 25 + 144

Evaluate the sum

h^2 = 169

Evaluate the exponent of both sides

h = 13

The cosine ratio is then calculated as:

cos(L) = KL/h

This gives

cos(L) =5/13

Hence, the value of the cosine ratio cos(L) is 5/13

Read more about right triangles at:

brainly.com/question/2437195

#SPJ1

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