All categories

2 years ago

Write a phrase as an algebraic expression six less than a number times 11

Mathematics

1 answer:

nadezda [96]2 years ago

7 0

Let the number = x

11x is 11 times the number. You are to take 6 less than this. Be careful how you read six less. It means the 6 is subtracted from the 11x

11x - 6 This is what you finally get.

You might be interested in

What additional information is necessary to prove that SILY is a parallelogram

kirza4 [7]

Answer:

Are the sides parallel?

Step-by-step explanation:

8 0

3 years ago

Plsssss help ASAP ;-;

lorasvet [3.4K]

Answer:

$3x+2$

Step-by-step explanation:

$6x^{2} - 11x - 10 = (2x - 5)(3x+2)$

So, $\frac{6x^{2} - 11x - 10}{2x-5} = \frac{(2x-5)(3x+2)}{2x-5}$

= $3x + 2$

Hope this helps :)

5 0

2 years ago

The convex polygon below has 8 sides. Find the value of x ?

bulgar [2K]

The missing interior angle, x, of the convex polygon is 168⁰.

<h3>Sum of interior angles of convex polygon</h3>

The sum of interior angles of a convex polygon is calculated as follows;

S = (n - 2) 180

S = (8 - 2) 180

S = (6) 180

S = 1080

The missing interior angle, x, is calculated as follows;

x + 126 + 146 + 130 + 140 + 146 + 134 + 90 = 1080

x + 912 = 1080

x = 1080 - 912

x = 168⁰

Learn more about interior angles of polygon here: brainly.com/question/24966296

5 0

1 year ago

Please show your work and explain it.

Maru [420]

Answer:

$f(x)=\dfrac{x+2}{2(x-2)}$

Step-by-step explanation:

Remember when you divide fractions, you need to get the reciprocal of the divisor and multiply. So your first simplification would be:

$\dfrac{x^2+4x+4}{x^2-6x+8}\div\dfrac{6x+12}{3x-12}\\\\=\dfrac{x^2+4x+4}{x^2-6x+8}\times\dfrac{3x-12}{6x+12}\\\\=\dfrac{(x^2+4x+4)(3x-12)}{(x^2-6x+8)(6x+12)}$

Next we factor what we can so we can further simplify the rest of the equation:

$=\dfrac{(x^2+4x+4)(3x-12)}{(x^2-6x+8)(6x+12)}\\\\=\dfrac{(x+2)(x+2)(3x-12)}{(x^2-6x+8)(6(x+2))}\\\\$

We can now cancel out (x+2)

$=\dfrac{(x+2)(3x-12)}{(x^2-6x+8)(6)}$

Next we factor out even more:

$=\dfrac{(x+2)(3)(x-4)}{(x-2)(x-4)(6)}$

We cancel out x-4 and reduce the 3 and 6 into simpler terms:

$=\dfrac{(x+2)(1)}{(x-2)(2)}$

And we can now simplify it to:

$=\dfrac{x+2}{2(x-2)}$

6 0

3 years ago

How do you solve domain and range

blsea [12.9K]

Your domain is your x and range is your y if that’s what you were asking you got to be more specific

8 0

2 years ago