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Bingel [31]
3 years ago
15

Write a phrase as an algebraic expression six less than a number times 11

Mathematics
1 answer:
nadezda [96]3 years ago
7 0

Let the number = x

11x is 11 times the number.  You are to take 6 less than this. Be careful how you read six less. It means the 6 is subtracted from the 11x

11x - 6 This is what you finally get.


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In a game the player wins if he rolls a 6 on a number cube .if the number cube is rolled 18 times then what is the reasonable
sp2606 [1]
<h2>Answer:</h2>

Prediction for the number of unsuccessful rolls is 15.

<h2>Step-by-step explanation:</h2>

There is \frac{1}{6} chance of rolling number 6 on the cube. If we want to find out what is the prediction for rolling number 6 in 18 rolls, we need to multiply 6*\frac{1}{6} which is 3. So if we roll a cube 18 times, we will probably got number 6 three times. When we subtract 3 from 18 (18-3), we get 15. That is the answer to your question.

I hope I helped you. I will be really happy, If you mark my answer as the brainliest.Your David

8 0
3 years ago
Justin is on a road trip. Over the past two days, he’s driven a total distance of 504 miles at an average speed of 56 miles/hour
irakobra [83]
Recall d  = rt, distance = rate * time.

now, he has a speed rate of 56 mph for a distance of 504

\bf d=rt\implies 504=56t\implies \cfrac{504}{56}=t\implies \stackrel{hours}{9}=t

so, at that speed the whole driving time is 9 hours then.  Ok, he drove 2 hours today, that means he drove 7 yesterday, 9 - 2.

how many miles is it for 7 hours at 56mph?  d = rt ---> d = 56 * 7

that many miles he drove yesterday.
8 0
3 years ago
The lifespan, in years, of a certain computer is exponentially distributed. The probability that its lifespan exceeds four years
kompoz [17]

Answer:

The correct answer is "0.300993e^{-0.300993x}".

Step-by-step explanation:

According to the question,

⇒ P(x>4)=0.3

We know that,

⇒ P(X > x) = e^{(-\lambda\times x)}

⇒     e^{(-\lambda\times 4)} = 0.3

∵ \lambda = 0.300993

Now,

⇒ f(x) = \lambda e^{-\lambda x}

By putting the value, we get

           =0.300993e^{-0.300993x}

3 0
3 years ago
Which equation below would be perpendicular to the line y = 2?
nadya68 [22]
Answer:
A) y=1/5x
Step-by-step explanation:
Coz, the way you identify a perpendicular line is by looking for its negative reciprocal. The neagtive reciprocal of 5= 1/5
Now, to check the ans we can multiply the negative reciprocal by "m"
(m in y=mx+c or y=mx+b)
in this case the "m" is stated as 5, so all we need to do is 1/5*5 if the ans is 1 then your ans is right....and over here it is
So thats how you identify & check perpendicular lines!
3 0
3 years ago
Read 2 more answers
A student records the number of hours that they have studied each of the last 23 days. They compute a sample mean of 2.3 hours a
natita [175]

Answer:

the standard deviation increases

Step-by-step explanation:

Let x₁ , x₂, .   .   .  , x₂₃ be the actual data observed by the student

The sample means  = x₁  +  x₂  +  .   .   .  , x₂₃ / 23

= \frac{x_1 +x_2 +...x_2_3}{23}

= 2.3hr

⇒\sum xi =2.3 \times 23 = 52.9hrs

let x₁ , x₂, .   .   .  , x₂₃  arranged in ascending order

Then x₂₃ was 10  and has been changed to 14

i.e x₂₃ increase to 4

Sample mean  = \frac{x_1 +x_2 +...x_2_3}{23}

\frac{52.9hrs + 4}{23} \\\\= \frac{56.9}{23} \\\\= 2.47

therefore, the new sample mean is 2.47

2) For the old data set

the median is x_1_2(th) values

[\frac{n +1}{2} ]^t^h value

when we use the new data set only x₂₃ is changed to 14

i.e the rest all observation remain unchanged

Hence, sample median = [{x_1_2]^t^h value remain unchange

sample median = 2.5hrs

The Standard deviation of old data set is calculated

=\sqrt{\frac{1}{n-1} \sum (xi - \bar x_{old})^2 } \\\\=\sqrt{\frac{1}{22}\sum ( xi - 2.3)^2 }---(1)

The new sample standard sample deviation is calculated as

= \sqrt{\frac{1}{n-1} \sum (xi-2.47)^2} ---(2)

Now, when we compare (1) and (2)  the square distance between each observation xi and old mean is less than the squared distance between each observation xi and the new mean.

Since,

(xi - 2.3)²  ∑ (xi - 2.47)²

Therefore , the standard deviation increases

6 0
3 years ago
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