Question

You play a game that involves drawing two numbers from a hat. There are 25 pieces of paper numbered from 1 to 25 in the hat. Each number is replaced after it is drawn. Find the probability that you will draw the 3 on your rst draw and a number greater than 10 on your second draw.

Answer 1

Answer:

$Probability=\frac{3}{125}$

Step-by-step explanation:

In the question,

Total number of pieces of paper numbered from 1 to 25 are = 25

As the draw also includes replacement.

So,

Probability of drawing '3' is given by,

$Probability=\frac{Favourable\,outcomes}{Total\,cases}\\Probability=\frac{1}{25}$

Now,

Numbers greater than 10 are = 15

So,

Probability of drawing a number greater than 10 is given by,

$Probability=\frac{15}{25}$

So,

Total probability is given by,

Product of probability of drawing 3 in 1st draw and the Probability of drawing a number greater than 10.

$\frac{1}{25}\times \frac{15}{25}=\frac{3}{125}\\Probability=\frac{3}{125}$